![\qquad\qquad\huge\underline{{\sf Answer}}](https://tex.z-dn.net/?f=%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D)
The given equation is a Quadratic equation, so it's graph must be a parabola, and the Coefficient of x² is positive that means the parabola must have an opening upward.
And 2 is added to the ideal equation, so the parabola must have shift 2 units up from x - axis.
From the above information, we can easily conclude that the Correct representation is done in graph 4
Answer:
I am so not good at math at all
+3 to both sides and you get s = -7
Answer:
see explanation
Step-by-step explanation:
Given
![\sqrt{\frac{4x^2}{3y} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B4x%5E2%7D%7B3y%7D%20%7D)
= ![\frac{\sqrt{4x^2} }{\sqrt{3y} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B4x%5E2%7D%20%7D%7B%5Csqrt%7B3y%7D%20%7D)
= ![\frac{2x}{\sqrt{3y} }](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B%5Csqrt%7B3y%7D%20%7D)
Rationalise the denominator by multiplying the numerator/ denominator by ![\sqrt{3y}](https://tex.z-dn.net/?f=%5Csqrt%7B3y%7D)
Note that
×
= a
=
× ![\frac{\sqrt{3y} }{\sqrt{3y} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3y%7D%20%7D%7B%5Csqrt%7B3y%7D%20%7D)
= ![\frac{2x\sqrt{3y} }{3y}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5Csqrt%7B3y%7D%20%7D%7B3y%7D)
2(2x +2y) and <span>√(4x + 4y)^2</span>