assume you want a line that goes through the given point and parallel to the given line. A line that is parallel to y=2/3 x + 5 will have the same slope. slope of that line is 2/3...the number in front of the x. So our new line will have slope of 2/3. now we need the y-intercept. To find that start with a slope intercept equation y=mx+b plug in the slope that we already know...it goes in for x...will be the number in front of x y= 2/3 x + b. now all we need is a number to plug in for the "b" and we will have it. to get the "b"...start with the part you already know. y = 2/3 x + b use the point they gave you...(-3,1)...and get x and y from it x will be -3 and y will be 1 plug that in 1= 2/3 ( -3) + b now we solve for b 1 = -2 + b 3 = b now we have the b we need y = 2/3 x + b y = 2/3 x + 3
You probably are interested in expressing the given equation as a quadratic equation in u, as it will make it easy to find the solutions.
Let u = x²
So,
u² = x⁴
So, the given equation can be written as:
u² - 17u + 16 = 0
Now the equation is quadratic in u and the solutions can be calculated using quadratic formula or factorization.
Well 75x12=900 so 900 divided by 40 is 22.5 so 22 teachers can have 40 chalks but the principal needs to order another 20 :)
wait do what? im confused
23. not equivalent because the first row 3x-9y=5 then if you multiplied this equation by 2 it will be 2(3x-9y) = 2(5) so 6x-18y= 10 not 6x-9y=10
24.equivalent because the second row 2y-6x=8 multiplied by 2 is 2(2y-6x)= 2(8) so 4y-12x=16
25. equivalent because the first row 5x+3y=19 multiplied by 2 is 2(5x+3y) = 2(19) SO 10X+6Y=38 and the second row 2x+4y=20 multiplied by 5 is 5(2x+4y)= 5(20) so 10x+20y=100
