You wold add both together and then divide by 5 so the equation would be 52+46=98 98/5=19.6 so the answer is 19.6
The arc sine of 0.5 is 30 degrees Therefore x = 30 degrees
The cosine of x = cosine of 30 degrees = 0.86603
(rounded to nearest hundredth is .87)
the complete question in the attached figure
<span>we have to find the surface area first</span>
<span>the area of the base is A1------- > 5*2=10 ft</span>²
A2 (area of two rectangles faces)---------- > 2*3+2*4=14 ft²
A3 (area of the two triangles faces)
base of triangle------------ > 5---------- > (x)+(x-5)
x²+h²=3² ------------ > h²=9-x²
(5-x)²+h²=4²----------- > h²=16-(5-x)²
9-x²=16-(5-x)²-------------- >9-x²=16-25-10x-x²----------------- > x=1.8
h²=9-(1.8)²------------ > h=2.4 ft
A3= (5*2.4)*2/2=12 ft²
the surface area total=A1+A2+A3=10+14+12=36 ft²
if $0.22 ------------------------ > 1 ft²
X----------------------------------> 36 ft²
X=36*.22=$7.92
the answer is $7.92
Answer:
α= 22°
β= 100°
Y= 50°
Step-by-step explanation:
Given are three different triangles,
In the first triangle, two of the angles are 38° and α° and the third angle would be 120°(using vertical opposite angle equal property).
We know sum of all three angles of a triangle
°
Substituting,

Similarly,
In the second triangle, two of the angles are 40° and 60° and the the angle we have to find is outside(β).
We know the outside angle is equal to the sum of opposite inside angles of a triangle.
Therefore,
β
In third triangle,'Y' is inside angle of the triangle and 70° and 160° are outside.
° makes linear pair,
sum of linear pair angles=
°
Therefore the angle of triangle next to
° would be
°
We see 'Y' is outside and opposite to both the inside angles
. thus applying the property,
°
Therefore 'Y' = 
Answer:
The correct answer is:
Ken will have run 3 laps and Hamid will have run 4.
Explanation:
To find this, we first find the number of seconds that will have passed when they meet again. We use the LCM, or least common multiple, for this. First we find the prime factorization of each number:
80 = 10(8)
10 = 5(2)
8 = 2(4)
4 = 2(2)
80 = 2(2)(2)(5)(2)
60 = 10(6)
10 = 5(2)
6 = 2(3)
60 = 2(2)(3)(5)
For the LCM, we multiply the common factors by the uncommon. Between the two numbers, the common factors are 2, 2 and 5. This makes the uncommon 2, 2, and 3, and makes our LCM
2(2)(5)(2)(2)(3) = 240
This means every 240 seconds they will both be at the start line.
Since Ken completes a lap in 80 seconds, he completes 240/80 = 3 laps in 240 seconds.
Since Hamid completes a lap in 60 seconds, he completes 240/60 = 4 laps in 240 seconds.