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3 years ago

(3x^2-5x)-(2n^2+2) (polynomials)

Mathematics

1 answer:

il63 [147K]3 years ago

6 0

(3n² - 5x) - (2n² + 2)
3n² - 2n² - 5x - 2
n² - 5x - 2

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Find the volume of the figure below.

Aliun [14]

Answer:

Step-by-step explanation:

Volume = Area of cross section x length

= (1/2 x 2 x 4) x 7

= 28

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3 years ago

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Lerok [7]

For both part A and part B, the cross-section would be a square.

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4 years ago

Solve: −3(5+8x)−20≤−11

Tatiana [17]

-3(5 + 8x) - 20 ≤ -11 |use distributive property: a(b + c) = ab + ac

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3 years ago

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Alla [95]

Answer:

Step-by-step explanation:

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3 years ago

an isosceles triangle ABC where AB=BC.the line BD is perpendicular to the line AC.given that the gradient of line AC=-2/3.find c

klemol [59]

To find the coordinate of A you can first determine the coordinate of D and apply the midpoint rule.

And to find the coordinates of D you must solve equations of AC and BD simultaneously.

AC has equation

$y=-\frac{2}{3} x+ \frac{20}{3}$

Or

$3y+2x=20 --(1)$

BD has equation

$y= \frac{3}{2}x -2$

Or

$2y-3x=-4 --(2)$

Multiply equation (1) by 2 and multiply equation (2) by 3 to obtain,

$6y+4x=40 --(3)$

$6y-9x=-12 --(4)$

Equation (3) minus equation (4)

gives

$13x=52$
$\therefore x=4$

Putting the value of x=4 in equation (4) gives

$6y-9(4)=-12$

This implies that

$6y-36=-12$

$6y=36-12$

$6y=24$
$\therefore y=4$

Solving the equations of AC and BD simultaneously give the coordinates of D to be;

$x= 4,y=4$

Let

$A(m,n)$ be the coordinates.

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$\frac{m+10}{2}=4$

and

$\frac{n+0}{2}=4$

Solving for m and n, we have

$m=4×2-10=-2$

And

$n=4×2=8$

Therefore A has coordinates

[tex] (-2,8)/tex]

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4 years ago