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vredina [299]
2 years ago
6

Kofi and kweku are two brothers. Kofi is older than kweku. Given that kofi's age is (5x-4) years and kweku's age is (2x+1) years

.
a. write down an expression, interns of x,for how much old is Kofi than kweku.
b. if Kofi is tens years older than kweku, find the value of x and the ages of Kofi and kweku
​
Mathematics
1 answer:
diamong [38]2 years ago
6 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the details :

Kofi is older than kweku

kofi's age = (5x-4) years

kweku's age = (2x+1) years

a. write down an expression, interns of x,for how much old is Kofi than kweku

Equate the ages of Kofi and kweku

(5x - 4) = (2x + 1)

5x - 4 = 2x + 1

5x - 2x = 1 + 4

3x = 5

3x - 5

B.) if Kofi is tens years older than kweku, find the value of x and the ages of Kofi and kweku

Then,

(5x-4) = (2x + 1) + 10

5x - 4 = 2x + 1 + 10

5x - 2x = 1 + 10 + 4

3x = 15

x = 5

Kofi's age : 5x - 4

5(5) - 4 = 25 - 4 = 21 years

Kweku's age : (2x + 1)

2(5) + 1 = 10 + 1 = 11 years

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I need help on questions 48 49 and 50 and u need to find the surface area of the 3 polyhedras please and thank you!
White raven [17]

48. The surface area of a cylinder is given by

... A = 2πr² + 2πrh = 2πr(r+h)

For r = 13 mi and h = 7 mi, this becomes

... A = 2π(13 mi)(13 mi + 7 mi) = 520π mi²

The surface area of the cylinder is 520π mi² ≈ 1634 mi².

49. The surface area of a rectangular prism is

... A = 2(LW + H(L+W))

For L = 20 m, W = 10 m, H = 7 m, this becomes

... A = 2((20 m)(10 m) + (7 m)(20 m + 10 m)) = 2(200 m² + 210 m²) = 820 m²

The surface area of the prism is 820 m².

50. The formula is the same as for problem 48.

For r = 10 m and h = 13 m, this becomes

... A = 2π(10 m)(10 m + 13 m) = 460π m² ≈ 1445 m²

The surface area of the cylinder is 460π m² ≈ 1445 m².

_____

When calculations are repetitive, it is convenient to let a calculator or spreadsheet do them.

7 0
3 years ago
The night watchman in a factory cannot guard both the safe in back and the cash register in front. The safe contains $6000, whil
Zolol [24]

Answer:

The guard should be positioned at the safe

Step-by-step explanation:

The night watchmen should be positioned to guard whichever place gives the highest expected value to the thief.

The expected value of robbing the safe is:

EV_{s} = \$ 6000*0.2\\EV_{s} = \$ 1200

The expected value of robbing the cash register is:

EV_{r} = \$ 1000*0.8\\EV_{r} = \$ 800

Therefore, the guard should be positioned at the safe since it yields a higher expected value to the thief in case he tries to rob it.

7 0
3 years ago
What is this answer?
zhannawk [14.2K]

I'm NOT 100% confident in my answers.

Graph 1:

Range: Option B

Graph 2:

Range: Option A

The range has to start at zero since that's the lowest point we can go, only one with zero is first option.

RATE AS BRAINLIEST

8 0
2 years ago
24 dogs to 56 cats<br><br><br> In the simplest form
Lubov Fominskaja [6]

Answer:

Simplify them to the lowest.

What's the GCF( Greatest Common Factor). It's 8. So divide both sides by 8.

24/8 = 3

56/8 = 7

so it's

3 dogs to 7 cats

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and
storchak [24]

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of <u>proportionality</u>, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

\frac{6.4^{2}}{156} k = 800

k=\frac{800.156}{96}

k = 1300

For the similar beam:

\frac{8.7^{2}}{L}1300=1300

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

6 0
3 years ago
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