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Naily [24]
3 years ago
13

It would be awesome for some help! :3 Johnny Uses a wheelbarrow to move planting soil to a delivery truck. The volume of plantin

g soil fits in the wheelbarrow measures 2 feet by 3 feet by 1.5 feet. The truck measures 11 feet by 8 feet by 6 feet. Johnny puts planting soil in the truck until it's 70% full. What is the minimum number of times Johnny needs to use the wheelbarrow until the truck is 70% full?
Mathematics
1 answer:
EleoNora [17]3 years ago
7 0
We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft

The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
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Answer:

\text{Volume of cat box}=3.52\text{ ft}^3

Step-by-step explanation:

We have been given that Mrs. Backstrom built a small wooden box for her cat. The box has a length of one and one tenth feet, a width of 1.6 feet, and a height of 2 feet. We are asked to find the volume of the box.

Let us convert one and one tenth feet into decimal.

1\frac{1}{10}=\frac{11}{10}=1.1

Since the cat box is in form of cuboid, so its volume will be equal to the product of length, width and height as:

\text{Volume of cat box}=1.10\text{ ft}\times 1.6\text{ ft}\times 2\text{ ft}

\text{Volume of cat box}=3.52\text{ ft}^3

Therefore, the volume of the cat box is 3.53 cubic feet.

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3 years ago
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3 years ago
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konstantin123 [22]

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Step-by-step explanation:

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Step-by-step explanation:

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<em>hope this helps!</em>

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