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Naily [24]
3 years ago
13

It would be awesome for some help! :3 Johnny Uses a wheelbarrow to move planting soil to a delivery truck. The volume of plantin

g soil fits in the wheelbarrow measures 2 feet by 3 feet by 1.5 feet. The truck measures 11 feet by 8 feet by 6 feet. Johnny puts planting soil in the truck until it's 70% full. What is the minimum number of times Johnny needs to use the wheelbarrow until the truck is 70% full?
Mathematics
1 answer:
EleoNora [17]3 years ago
7 0
We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft

The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
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Someone help pretty please!
Nonamiya [84]
The answer is choice B
y > (2/3)x + 1

The boundary line is the equation y = (2/3)x + 1 which can be found through the slope formula to get m = 2/3. Then you use one of the two points on the line to find b = 1. 

The equal sign in y = (2/3)x + 1 changes to a "greater than" sign to indicate two things
A) The shaded region is above the boundary line
B) The boundary line itself is a dashed line to indicate "no solution points on this line"
4 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
A rectangular swimming pool has an area of (70x+10) square feet. Find possible dimensions of the pool.
NNADVOKAT [17]

Answer:

10 and 7x + 1

Step-by-step explanation:

The area of a rectangle is 70x + 10.

Let's factor 70x + 10.

Factor out a common factor of 10.

70x + 10 = 10(7x + 1)

Since the area of a rectangle is length * width, we can let one factor be the length and the other factor be the width.

Possible dimensions are 10 and 7x + 1

6 0
3 years ago
Read 2 more answers
A map of a park has a scale of 1 inch to 1,000 feet. Another map of the same park has a scale of 1 inch to 500 feet. Which map i
DENIUS [597]

Answer:

1 inch to five hundred feet

Its just like fractions, which ever one is lower has the greater value in ratio

3 0
3 years ago
Here's the rest of my points for anyone who wants them :)
kramer

Answer:

7

Step-by-step explanation:

line in the middle is an angle bisector

14/6 = 21 / 3x - 12

first, cross multiply

14 (3x - 12) = 6*21

Remove the brackets

42x - 168 = 126

Add 168 to both sides

42x = 168 + 126

Combine

42x = 294

Divide by 42

x = 294/42

x = 7

chegg

brainly.com/question/16979551?utm_source=android&utm_medium=share&utm_campaign=question

3 0
2 years ago
Read 2 more answers
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