Answer:
Below in bold.
Step-by-step explanation:
No repetition.
There are a total of 7 numbers.
For the number to be even it must end in 0, 2 or 8.
The other 3 numbers will be the number of permutations of 3 from the 6 other numbers.
Number of 4 digit numbers ending in 0
= 6P3 = 6! / 6-3!
= 120.
Now the number could also end in 2 or 8,
so there are 3*120 = 360 4-digit even numbers (no repetition).
With repetition.
There are 3 * 7^3 = 1029 with repetition.
