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Archy [21]
2 years ago
14

How many 4-digits number can be formed out of 0,1,2,3,5,7 and 8. If:

Mathematics
1 answer:
Bad White [126]2 years ago
5 0

Answer:

Below in bold.

Step-by-step explanation:

No repetition.

There are a total of 7 numbers.

For the number to be even it must end in 0,  2 or 8.

The other 3 numbers will be the number of permutations of 3 from  the 6 other numbers.

Number of 4 digit numbers ending in 0

= 6P3 = 6! / 6-3!

= 120.

Now the number could also end in 2 or 8,

so there are 3*120 = 360 4-digit even numbers (no repetition).

With repetition.

There are 3 * 7^3 = 1029  with repetition.

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<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>4</em><em>2</em>

<em>Question</em><em> </em><em>2</em><em>)</em><em> </em><em>8</em><em>+</em><em>9</em>

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Step-by-step explanation:

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