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Anna [14]
3 years ago
7

If K(-1, 2) is reflected over the x-axis, then the image is K'

Mathematics
2 answers:
musickatia [10]3 years ago
6 0

Answer:

(K'(- 1, - 2 )

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y )

Thus

K(- 1, 2 ) → K'(- 1, - 2 )

Marizza181 [45]3 years ago
4 0
K=(-1,2) -> (-1,-2) because it will be crossing the x axis which will change the position of the point making it both negative because it will be in a new axis
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PLEASE HELP ASAPPPP!!!!
Musya8 [376]

Length is The formula for volume of a prism is:

Volume = length x width x height

In this case

Length is 17 inches

Width is 7 inches

Height is 7 inches

^^^Plug these numbers into the volume formula given above:

Volume = 17 * 7 * 7

Volume = 833

Volume for this prism is 833 in³

Hope this helped!

~Just a girl in love with Shawn Mendes

8 0
3 years ago
Let ​f(x)= -5x+6. Find and simplify ​f(3n−5​). <br><br> f(3n-5)= ?
IRINA_888 [86]
We know that our function is f(x)=-5x+6; the only thing we need to find f(3n-5) is replace x with (3n-5) in our original function:
f(x)=-5x+6
f(3n-5)=-5(3n-5)+6

Now, lets simplify our function:
f(3n-5)=-15n+25+6
f(3n-5)=-15n+31

After simplify our function, we can conclude that f(3n-5)=-15n+31

5 0
3 years ago
*20 points*
sergeinik [125]

Answer:

c=9

d=3

Step-by-step explanation:

We have been asked:

What value of c makes x2 + 6x + c a perfect square trinomial?

c =  

If x2 + 6x + c = (x + d)2, then d =

First step we have to do is divide the coefficient of x by 2. The coefficient is 6

6/2 = 3

Now take the square of 3 = 3^2

3^2 = 3*3 =9

The value of c is 9

If x^2 + 6x + c = (x + d)^2, then d =?

Put the value of c in the equation:

x^2+6x+9

Take the square root of 1st and third term. Then the expression can be written as:

x^2+6x+9 = (x+3)^2

Thus the value of d is 3.

If x^2 + 6x + 9 = (x + 3)^2, then d = 3 .....

6 0
3 years ago
Find the domain and range !!! 10 points math 3
zimovet [89]

Answer:

The domain = (-∞ , -1/4) ∪ (-1/4 , ∞)

The range = (-∞ , 21/4)∪(21/4 , ∞)

The answer is not in the choices

Step-by-step explanation:

* Lets revise how to find the inverse function

- At first write the function as y = f(x)

- Then switch x and y

- Then solve for y

- The domain of f(x) will be the range of f^-1(x)

- The range of f(x) will be the domain of f^-1(x)

* Now lets solve the problem

- At first find the domain and the range of f(x)

∵ f(x) = (x - 9)/(21 - 4x)

- The domain is all real numbers except the value which

  makes the denominator = 0

- To find this value put the denominator = 0

∴ 21 - 4x = 0 ⇒ subtract 21 from both sides

∴ -4x = -21 ⇒ ÷ -4 both sides

∴ x = 21/4

∴ The domain = R - {21/4} OR the domain = (-∞ , 21/4)∪(21/4 , ∞)

* Now lets find the range

- The range will be all the values of real numbers except -1/4

 because the horizontal asymptote equation is y = -1/4

- To find the horizontal asymptote we find the equation y = a/b

 where a is the coefficient of x up and b is the coefficient of x down

∵ The coefficient of x up is 1 and down is -4

∴ The equation y = 1/-4

∴ The value of y = -1/4 does not exist

∴ The range = R - {-1/4} OR the range = (-∞ , -1/4) ∪ (-1/4 , ∞)

* Switch the domain and the range for the f^-1(x)

∴ The domain = (-∞ , -1/4) ∪ (-1/4 , ∞)

∴ The range = (-∞ , 21/4)∪(21/4 , ∞)

4 0
3 years ago
Please help!
valina [46]

Answer:

1.Corresponding angles theorem

2.Linear postulate

3.By the definition of supplementary angles

Step-by-step explanation:

We are given that  

w\parallel xand y is a transversal.

We have to prove \angle 3 and angle 5 are supplementary

Proof:

1.Given that w\parallel x and y is a transversal.

We know that \angle 1\cong \angle 5

Reason:Corresponding angles theorem

Therefore, m\angle 1=m\angle 5

by the definition of congruent.We also know that, by definition, angle 3 and angle 1 are a linear pair.

Therefore, they are supplementary by linear pair postulate

By the definition of supplementary angles

m\angle 3+m\angle 1=180^{\circ}

Now, we can substitute m\angle 5=m\angle 1

Then, we get

\m\angle 3+m\angle 5=180^{\circ}

Therefore, by the definition of supplementary angles,angle 3 and angle 5 are supplementary

5 0
3 years ago
Read 2 more answers
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