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julsineya [31]
3 years ago
13

Cells are able to remove large amounts of material using what cell process?

Biology
1 answer:
ankoles [38]3 years ago
6 0

Answer:

Exocytosis

Explanation:

Exocytosis is the process that allows cells to be able to remove large amounts of material in and out of themselves.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

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3. Which of the following would best support the theory of evolution?
faltersainse [42]

The theory of evolution will be best supported by the evidence showing a species changes over time. Thus, option A.

Basic evidences for proving the theory of evolution are anatomy, Biological morphology, Fossils and direct observations. There have been various theories for the proof of evolution like structural similarities in an embryo formation pointed towards common ancestors. Theory of Natural selection embarked by Charles Darwin to show genetic variations picked by organisms in whole population.

The most authentic theory over evidence for evolution is Paleontological theory which includes study, observation and acquired prove of fossils of various organisms in the forms of Petrified, mold and cast, trace fossils, compression fossils, impression fossils, etc.

Learn more about Theory of evolution here brainly.com/question/4207376

6 0
1 year ago
The plant kingdom is divided into 2 groups vascular and nonvascular. describe each subclass. include key words such as vascular
BaLLatris [955]
<h2>Vascular and Nonvascular Plants </h2>

Explanation:

Kingdom Plantae on the basis of vasculature is divided into two groups-vascular and non-vascular plants .

  • <u>Vascular plants </u>or tracheophytes have a proper tissue-level organization and true shoot and root structures like leaves, stem, flowers, root etc
  • The tissue system or vasculature of vascular plants compromises of vascular tissues like tubular vessels – xylem and phloem
  1. The xylem transports nutrients to various parts of the body from the leaves.
  2. Phloem conducts water and other nutrients from the roots to various parts of the plant .
  • These are flowering plants that include the phanerogams – angiosperms and gymnosperms and bears flowers and fruits like the cedars, pine, clubmosses, lilies, sunflower etc.
  • Dicots are with tubular vasculature.  
  • Non-vascular plants or bryophytes with an absence of proper tissue-level organization and true shoot or root systems
  • <u>Nonvascular plants</u> are small. Their transport mechanism is poor due to lack of vascular tissues
  • These plants are lack proper shoot or root system.
  • It includes mosses, hornworts etc.
  • Monocots are plants with scattered tube-like vessels .
3 0
3 years ago
To measure the population density of monarch butterflies occupying a particular park, 100 butterflies are captured, marked with
Sav [38]

Answer:

Given merely 40 butterflies were marked, assumed that there were multiple captures of both marked and unmarked butterflies, that the butterflies caught in traps were on the loose to be caught again. There are two mathematical solutions for this, both yielding the same answer which is 100. 

• First, to each marked butterfly was taken twice (40 marked X2 = 80 captured) then of the unmarked butterflies the 120 captured must relate to 60 actual butterflies. In which 40 + 60 = 100. 

• Secondly, by means of ratios in which 80/200 = 40/X. In this case X also = 100 that will result to the estimated size of the population of wilson park is 100.

Explanation:

3 0
3 years ago
Pls answer whole page plz
madreJ [45]
1. air is warmed near earth's surface
2. water vapor rises and comes in contact with cooler air
3 water vapor condenses onto partials etc.
4 water enters the atmosphere through evaporation
5 clouds are born

warm air can “hold” more water vapor than cool air because as the air warms its molecules move farther apart, making room for more molecules. This leads to the idea that as air cools its molecules move closer together, “squeezing” out water vapor.
6 0
3 years ago
Students are measuring the jump height and length of their back legs to see if there is a connection. They will measure both the
Talja [164]
A. The height of your back legs will probably not change throughout the experiment, but your jump height may so you will add each of the jump heights together and divide by the amount of times jumped. Hope this helped
8 0
3 years ago
Read 2 more answers
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