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OLga [1]
3 years ago
8

A rigid sphere is falling from a height of 1m in a fluid of density 1000 m3/kg. The time it took to fall is 500 seconds. If the

density of the sphere is 1100 m3/kg and the viscosity of the fluid is 100 cP, what is the diameter of the sphere? (a. 6.1 m , b. 0.61 m , c. 0.061 m , d. 0.0061 m)
Chemistry
1 answer:
Allisa [31]3 years ago
8 0

Answer:

0.00191 meter is the diameter of the sphere.

Explanation:

Velocity of the rigid sphere = v=\frac{1m}{500 s}

Density of the fluid = \rho _f=1000 kg/m^3

Density of the particle= \rho _p=1100 kg/m^3

Viscosity of the fluid =\eta =100 centiPoise = 1 Poise=0.1 Kg/(m s)

Radius of the sphere  = r

v=\frac{2}{9}\times \frac{\rho _p-\rho _f}{\eta }gr^2

(Terminal velocity)

\frac{1 m}{500 s}=\frac{2}{9}\times \frac{1100 kg/m^3-1000 kg/m^3}{0.1 kg/(m s)}\times 9.8 m/s^2\times r^2

r = 0.00191 m

0.00191 meter is the diameter of the sphere.

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