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natita [175]
3 years ago
12

A molecule, that is sp3d2 hybridized and has a molecular geometry of square pyramidal, has ________ bonding groups and ________

lone pairs around its central atom a molecule, that is hybridized and has a molecular geometry of square pyramidal, has ________ bonding groups and ________ lone pairs around its central atom 5, 1 4, 2 4, 1 3, 2 2, 3
Chemistry
1 answer:
bogdanovich [222]3 years ago
8 0

<u>Answer:</u> The correct answer is 4, 2.

<u>Explanation:</u>

Hybridization is calculated by using the formula:

\text{Number of electron pairs} =\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

It is given that the hybridization of a molecule is sp^3d^2, this means that the number of electron pairs are 6. The molecular geometry of the molecule having electron pairs as 6 is octahederal.

If the molecular geometry of the molecule is square pyramidal, then it would acquire 4 electron pairs as the bonding groups and the rest pairs would be considered as lone pairs.

Hence, the correct answer is 4, 2.

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Where;
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            Ru  =  Central Metal Atom  =  <span>Ruthenium

            CN  =  Cyanide Ligand

            CO  =  Carbonyl Ligand

The charge on Ru is calculated as follow,

                               Ru + (CN) + (CO)</span>₄  =  -1
Where;
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So, Putting values,


                               Ru + (-1) + (0)₄  =  -1

                               Ru - 1 + 0  =  -1

                               Ru - 1  =  -1

                               Ru  =  -1 + 1

                               Ru  =  0
Result:
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