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natita [175]
3 years ago
12

A molecule, that is sp3d2 hybridized and has a molecular geometry of square pyramidal, has ________ bonding groups and ________

lone pairs around its central atom a molecule, that is hybridized and has a molecular geometry of square pyramidal, has ________ bonding groups and ________ lone pairs around its central atom 5, 1 4, 2 4, 1 3, 2 2, 3
Chemistry
1 answer:
bogdanovich [222]3 years ago
8 0

<u>Answer:</u> The correct answer is 4, 2.

<u>Explanation:</u>

Hybridization is calculated by using the formula:

\text{Number of electron pairs} =\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

It is given that the hybridization of a molecule is sp^3d^2, this means that the number of electron pairs are 6. The molecular geometry of the molecule having electron pairs as 6 is octahederal.

If the molecular geometry of the molecule is square pyramidal, then it would acquire 4 electron pairs as the bonding groups and the rest pairs would be considered as lone pairs.

Hence, the correct answer is 4, 2.

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Concentration :

196 g/L and 4 N

<h3> </h3><h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

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\tt mol=M\times V=2\times 0.5=1

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\tt mass=mol\times MW=1\times 98=98~g

concentration in g/L :

\tt \dfrac{98}{0.5}=196~g/L

concentration in normality

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so :

\tt N=2\times 2(n=2~for~H_2SO_4\rightarrow 2H^+)\\\\N=4

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Considered this question: what is the mass of solute in 200.0 L of a 1.556-M solution of KBR?
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Hey there!:

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