Answer:
x = 8
Step-by-step explanation:
Δ TSU and Δ TRV are similar , thus the ratios of corresponding sides are equal, that is
= 
, substitute values
= 
= 
( cross- multiply )
3x = x + 16 ( subtract x from both sides )
2x = 16 ( divide both sides by 2 )
x = 8
Answer:
x1=3 x2=-5
BUT x1=3 is not an answer because it doesnt respects the range on the original ecuation, so x2=-5 is the solution
Step-by-step explanation:
Answer:
Happy new year to you and your family and
1) Find whether the function, f(x) has a local or absolute maximum or minimum.
Calculate the first derivative: f '(x) = 3x^2 + 8
Maximum or minimum => f '(x) = 0 => 3x^2 + 8 = 0 => 3x^2 = -8
Which has not a real solution because x^2 is always positive.
Then there is not maximum or minimum.
Then that function is or increasing or decreasing in all the domain and it can have maximum one real root.
Yet we have to show if there is one root or none root.
if you make x = 1 you find f(x) = 1^3 + 8(1) -19 = 1 +8 - 19 = -10
If you make x =2, you find f(x) = 2^3 + 8(2) -19 = 8 + 16 - 19 = 5
Then f(x), given that it is continuos, will have a zero between x =1 and x = 2, which corresponds to the only root of the function.
The answer is $30.
We know discounted price of the shoes - $24.
We need to find out the original price of the shoes - x.
The discounted price is 80% of the original price (it is said that <span>shoes have been discounted 20%, so 100-20= 80%).
Let's set up a proportion. If $24 is 80%, how much is 100% (the original price):
$24 : 80% = x : 100 %
After crossing the products:
x = $24 * 100% / 80% = $30
Let's just check the result. After the discount of 20%, shoes will cost:
$30 - 20% = $30 - $30*(20/100) = $30 - $6 = $24.
</span><span>The original price of the shoes is $30.</span>
