The area of the semicircle is A = 1187.9 cm².
<h3>What is the area of a circle?</h3>
The area of a circle with a radius of r is A = πr².
Given that, the diameter of the semicircle is 55 cm.
The radius of the semicircle is,
r = 55/2
The area of a semicircle is given by,
A = (1/2)πr²
Substitute the values,
A = (1/2)π(55/2)²
A = 1187.9
Hence, the area of the semicircle is A = 1187.9 cm².
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Answer:
Hello there!
The answer to your question is :
<em>C: Finn needs 6 cups of sugar for 4 cakes.</em>
<em>D: Finn needs 1 1/2 cups of sugar for 1 cak</em>e.
Step-by-step explanation:
The graph clearly shows ( sides cups of sugar) (bottom number of cakes)
For sugar you need 6 cups to make 4 cakes
For sugar on the second question you need 1 1/2 cups of sugar to make 1 cake
Multiply 1 1/2 times 6 then divide and your answer is 4. That's 4 cakes out of 6 cups of sugar out of the original cups of sugar ( 1 1/2)
This is the confirmed answer I took the quiz and got 100%
Hopes this helps you!
~Darlington
Hello!
The Correct Answer to this is that <span>7 divided by 20 or 7/20 equals:
"7/20 = 0.35"
</span>Explanation:
Since you are trying to find equivalent values for 7/20, you can make two proportions and set them equal to each other. The following states that "7 out of 20 is equal to some amount out of 100."
<span><span>7/20</span>=<span>x/100</span></span>
Solve by cross multiplying:
<span>20x=700</span>
Divide both sides by 20 to isolate x:
<span>x=35</span><span> Therefore, </span><span><span>7/20</span>=<span>35/100</span></span><span>. This is the same as saying 35%, since by definition "per" means out of, and "cent" means hundred. To make it into a decimal just move the decimal place two digits to the left, such that 35.00 becomes 0.35, and 100.00 becomes 1. Then it is simply </span><span>0.35/1</span><span>, or 0.35</span>
<span>
Hope this Helps! Have A Wonderful Day! :)</span>
Answer:
Hisoka FS no doubt he is most def BRAINLIEST???
Answer:
Question 1 = 32.4ft Question 2 = 72ft Question 3 = 288ft
Step-by-step explanation:
Use multiplication.