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3 years ago

Two tangents each intersect a circle at opposite

Mathematics

2 answers:

Oksana_A [137]3 years ago

6 0

Answer:

No. They are parallel and parallel lines don't intersect each other.

Step-by-step explanation:

-The two tangents intersect the circle at it's diameters endpoints.

-Tangents are always perpendicular to the radius.

-Since, both tangents meet the circle perpendicularly at the extreme ends of the diameter, they have a parallel relationship.

-Parallel lies don't intersect.

-Hence, the tangents won't intersect at any point since they are parallel.

Monica [59]3 years ago

5 0

Answer:

No, the tangents cannot intersect outside of the circle. When tangents intersect outside of a circle, the measure of the angle they form is one half the difference of the intercepted arcs. So as a result, both intercepted arcs would have to measure 180 degrees which would make two tangents intersecting outside of the circle, improbable.

Step-by-step explanation:

I just did this question on edg ang got it right. I hope this helps somebody!!

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Answer:

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Step-by-step explanation:

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3 years ago

What happens to the graph of the line y = mx + b if the value of b is decreased?

ollegr [7]

Answer:

The lines moves lower.

Step-by-step explanation:

The steepness of a line is related to the slope, m.

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b is where the line intersects the y-axis.

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2 years ago

Find x so that x, X +2, X'+3 are the first three terms of a geometric sequence. Then find the 5" term of the

velikii [3]

Answer:

The fifth term is -1/4.

Step-by-step explanation:

We know that the first three terms of the geometric sequence is x, x + 2, and x + 3.

So, our first term is x.

Then our second term will be our first term multiplied by the common ratio r. So:

$x+2=xr$

And our third term will be our first term multiplied by the common ratio r twice. Therefore:

$x+3=xr^2$

Solve for x. From the second term, we can divide both sides by x:

$\displaystyle r=\frac{x+2}{x}$

Substitute this into the third equation:

$\displaystyle x+3=x\Big(\frac{x+2}{x}\Big)^2$

Square:

$\displaystyle x+3 = x\Big( \frac{(x+2)^2}{x^2} \Big)$

Simplify:

$\displaystyle x+3=\frac{(x+2)^2}{x}$

We can multiply both sides by x:

$x(x+3)=(x+2)^2$

Expand:

$x^2+3x=x^2+4x+4$

Isolate the x:

$-x=4$

Hence, our first term is:

$x=-4$

Then our common ratio r is:

$\displaystyle r=\frac{(-4)+2}{-4}=\frac{-2}{-4}=\frac{1}{2}$

So, our first term is -4 and our common ratio is 1/2.

Then our sequence will be -4, -2, -1, -1/2, -1/4.

You can verify that the first three terms indeed follow the pattern of x, x + 2, and x + 3.

So, our fifth term is -1/4.

4 0

3 years ago

Write the rate as a unit rate: 400 miles in 8 hours

nikdorinn [45]

Answer:

50miles/hour

Step-by-step explanation:

400/8 is 50.

4 0

3 years ago

A 20 ft. ladder is used against a 15 ft. wall. What is the measure of the angle made by the ladder and the ground (nearest whole

Brrunno [24]

Step-by-step explanation:

Given that,

The length of a ladder, H = 20 feet

The height of the wall, h = 15 ft

We know that,

$\sin\theta=\dfrac{h}{H}$

h is perpendicular and H is hypotenuse

So,

$\sin\theta=\dfrac{15}{20}\\\\\theta=\sin^{-1}(\dfrac{15}{20})\\\\\theta=48.59^{\circ}$

Now using Pythagoras theoerm,

$b=\sqrt{H^2-h^2}\\\\b=\sqrt{20^2-15^2}\\\\b=13.2\ ft$

Hence, the angle made by the ladder and the ground is 48.59° and the ladder is 13.2 feet from the wall on the ground.

6 0

3 years ago