1. If we cross YyLl (heterozygous parent with dominant traits) with yyll (homozygous parent with recessive traits)
P: YyLl x yyll
F1 generation: YyLl: 400 Yyll: 100 yyLl: 100 yyll: 400
Recombinant offspring are those children whose genes contain a non-parental allele combination (neither allele group is directly inherited from either parent). This happens when genes are located on the same chromosome but are so far apart from one another so that their alleles get crossed over during meiosis. In this case, Yyll and yyLl are the recombinant.
2. Calculation of distance between Y and L.
The numbers of the two recombinant types is 200 (100 Yyll + 100 yyLl) and 800 parental offspring.
Total number of offspring is 1000.
So: 200/1000*100=20 map units.
There is 20 percent recombinant offspring frequency.
Answer:
The answer is D i think :)
RrXtXt×RrXTY is representing the cross between the white eyed female and red eyed male.
Option D
<h3><u>Explanation:</u></h3>
The genes that are discussed here both are completely dominant over their recessive alleles. In the autosome, the dominant R gene is responsible for red eye and recessive r gene is responsible for sepia eye. But in allosome, the dominant T gene allows the eye colour to be expressed and the recessive t gene doesn't allow eye colour to be expressed and makes it white.
As the female do have 2 X chromosomes and the female is white eyed, then both the chromosomes of female have t gene.
As the male is red eyed and have one X chromosome, so the male must have atleast one R gene in autosome to make the eye colour red and must have T gene in his X chromosome to make it appear in phenotype.
So the most possible cross that is given here is RrXtXt×RrXTY.
This is not a question. Do you need anything answered?
However, It would be bright all around. All though the Apollo astronauts that went there, it wasn't as bright as say a desert on Earth but more like an asphalt parking lot.
