3 years ago

Help me please! It’s number 45.

1 answer:

nalin [4]3 years ago

8 0

I’m pretty sure it this if not sorry

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spin [16.1K]

Answer:

8.5 or 4.25 i think pretty sure its 8.5 tho

Step-by-step explanation:

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3 years ago

Vilka [71]

Miguel spent the most of his savings.

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3 years ago

Serjik [45]

Answer: 0.27648

Step-by-step explanation:

Given : The proportion of all individuals have group A blood : p=0.040

Total individuals give blood : n= 6

Let X be the number of individuals have group A blood.

Since all individual are independent of each other.

$X\sim Bin(n=6, p=0.40)$

Formula : $P(X=x)=^nC_xp^x(1-p)^{n-x}$ , where n= sample size , p = probability of getting success in each trial.

The probability that exactly three of the individuals have group A blood. :

$P(x=3)= ^6C_3(0.40)^3(1-0.4)^3\\\\= \dfrac{6!}{3!3!}\times(0.40)^3(0.60)^3\\\\=0.27648$

The probability that exactly three of the individuals have group A blood. is 0.27648

8 0

3 years ago

Anon25 [30]

Answer

-1(3a-2)

Step-by-step explanation:

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3 years ago

ryzh [129]

Answer:

use the formula given in the pic and you will get the answer

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3 years ago