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olganol [36]
3 years ago
8

Which is not an equation of the line going through (3, -6) and (1,2)

Mathematics
2 answers:
True [87]3 years ago
7 0
Answer is A.
You can find the answer by plugging in X and Y to the equations




omeli [17]3 years ago
5 0

Answer:

The correct option is <u>A) y - 1 = -4(x-2)</u> is an equation of the line going through (3, -6) and (1,2)

Step-by-step explanation:

we have to find which is not an equation of the line going through (3, -6) and (1,2)

Put   (3, -6) and (1,2) in Part A)

y - 1 = -4(x-2)

for (3, -6)

-6 - 1 = -4(3-2)

-7 ≠ -4

for (1,2)

2 - 1 = -4(1-2)

    1 = -4(-1)

     1 ≠ 4

This is not an equation of the line going through (3, -6) and (1,2)

Put   (3, -6) and (1,2) in Part B)

y - 2 = -4(x-1)

for (3, -6)

-6 - 2 = -4(3-1)

-8 = -8

for (1,2)

2 - 2 = -4(1-1)

    0= 0

This is an equation of the line going through (3, -6) and (1,2)

   

Put   (3, -6) and (1,2) in Part C)

y + 6 = -4(x-3)

for (3, -6)

-6 + 6 = -4(3-3)

       0 = 0

for (1,2)

2 + 6 = -4(1-3)

    8= 8

This is an equation of the line going through (3, -6) and (1,2)

   

Put   (3, -6) and (1,2) in Part D)

y  = -4x + 6

for (3, -6)

-6  = -4(3) + 6

       -6 = -6

for (1,2)

2  = -4(1) + 6

 2 = 2

This is an equation of the line going through (3, -6) and (1,2)

Hence, The correct option is <u>A) y - 1 = -4(x-2)</u> is an equation of the line going through (3, -6) and (1,2)

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