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lara [203]
3 years ago
10

Find the perimeter of a quadrilateral with vertices at C (−1, 2), D (−2, −1), E (2, −2), and F (1, 1). Round your answer to the

nearest hundredth when necessary.
Mathematics
1 answer:
expeople1 [14]3 years ago
7 0
To get the perimeter of the quadrilateral, the distance formula can be used. We simply have to subtract the y coordinate of one point to another and the same for the x coordinate. The square root of the sum of the squares of the difference is the distance.The results can then be added to get the perimeter. So,
CF = sqrt ( (2-(-1))^2 + (-1-(-2))^2 ) = sqrt(10)
FE = sqrt ( (-2-1)^2 + (2-1)^2 ) = sqrt(10)
ED = sqrt ( (-1-(-2))^2 + (-2-2)^2 ) = sqrt(17)
DC = sqrt ( (2-(-1)^2 + (-1-(-2))^2 ) = sqrt(10)

P = CF + FE + ED + DC = sqrt(10) + sqrt(10) + sqrt(17) + sqrt(10) = 13.61

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If I buy 3 4/5kg of cherries and 2 1/4 of strawberry's what is the Mass kilograms of fruit
lisov135 [29]
If you would like to know how many kilograms of fruit do you have, you can calculate this using the following steps:

3 4/5 kg of cherries + 2 1/4 kg of strawberries = 3 4/5 + 2 1/4 = 19/5 + 9/4 = 76/20 + 45/20 = (76 + 45) / 20 = 121/20 = 6 1/20 kg of fruit

The correct result would be 6 1/20 kilograms of fruit.
3 0
4 years ago
One morning, John drive 5 hours before stopping to eat. After lunch, he. increased his speed by 10 mph. If he completed a 500-mi
Marrrta [24]
So  he drove 5hrs, before lunch, now, he was going at speed, say "r", after he ate, he sped up by 10mph, so, his rate is whatever "r" is, plus 10, or " r + 10 ", after lunch

we know the whole trip took 10hrs, so, is 5hrs before lunch and 5hrs after lunch

we also know the whole trip was 500miles, so if he drove, say "d" miles before lunch, after lunch he drove the slack after lunch, or " 200 - d "

recall, your d = rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{before lunch}&d&r&5\\
\textit{after lunch}&500-d&r+10&5
\end{array}
\\\\\\

\begin{cases}
\boxed{d}=5r\\
500-d=(r+10)5\\
----------\\
500-\boxed{5r}=(r+10)5
\end{cases}
\\\\\\
\cfrac{500-5r}{5}=r+10\implies 100-r=r+10

and I'm sure you know what that is
6 0
3 years ago
Which sums are equal to 1hold 6/8?
katovenus [111]
A. = 7/8
b. = 7/4 = 1 3/4
c. = 7/4 = 1 3/4
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= b,c,d
6 0
4 years ago
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Serjik [45]

Constant is otherwise called term independent. It should not contain any other letters.

So, a constant without a variable best describes a constant.

5 0
3 years ago
Show different ways you can make 7502
Bingel [31]
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6,000+1,500+2



6 0
4 years ago
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