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lozanna [386]
3 years ago
12

How do I decompose the number 740

Mathematics
1 answer:
harina [27]3 years ago
3 0
Divide by the smallest number that can go into it
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PLEASE HELP QUICK!!
egoroff_w [7]

Answer:

B. (4x+5)(16x2−20x+25)

Step-by-step explanation:

64x3+125

=(4x+5)(16x2−20x+25)

7 0
2 years ago
Kevin has 3 fewer leaves than sandy. Sandy has 3 leaves. How many leaves does Kevin have?
chubhunter [2.5K]

Answer:

0 leaves

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A science experiment calls for a mixture of 400 mL of liquid A, 2.5 L of liquid B, 650 mL of liquid C, and 1 L of liquid D. Whic
IceJOKER [234]

Answer:

5L.

Step-by-step explanation:

This is because there are 1000 mL in an L so .4 + 2.5 + .65 + 1 = 4.55 which is then rounded up to 5L.

5 0
3 years ago
CAN ANYONE SOVE THIS EASY INDIAN MATHS QUESTION...The angle of elevation of a cloud from a point 60m above a lake is 30" and the
guajiro [1.7K]

Answer:

the angle of elevation of a cloud from a point 60m above a lake is 30 and the angle of depression of the reflection of the cloud in the lake is 60 - Mathematics ... the reflection of the cloud in the lake is 60* find the height of the cloud from the surface of the lake

Step-by-step explanation:

Hope this helps

3 0
2 years ago
Read 2 more answers
It takes 20 hours and $400 to interview a candidate, and it takes 120 hours and $3600 to train an employee. A company has less t
zavuch27 [327]
<span>Let C denote the number of candidates they interview and E the number of employees they train.
</span>
<span>If it takes 20 hours and $400 to interview a candidate, then it takes 20C hours and $400C to interview C candidates.
</span>
If <span>it takes 120 hours and $3600 to train an employee, then it takes 120E hours and $3600E to train E employees.
</span>
Company has less than <span>$95000, then 400C+3600E<95000.
</span>
Company <span>wants to spend at most 470 hours, then 20C+120E\le&#10; 470.
</span>
<span>You obtain the system of two inequalities:
</span>

\left \{ {{400C+3600E\ \textless \ 95000} \atop {20C+120E\le&#10; 470}} \right.  \\  \left \{ {{4C+36E\ \textless \ 950} \atop {C+6E\le &#10;23.5}} \right. \\ \left \{ {{4C+36E\ \textless \ 950} \atop {4C+24E\le &#10;94}} \right.
Then you can solve this system according to your demands.






3 0
3 years ago
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