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Tatiana [17]
3 years ago
15

Which equation corresponds to the statement, to more than a number equivalent to Y

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

English statement 'two more than a number equivalent to Y' can be algebraically represented as:

  • y = x + 2

Step-by-step explanation:

Two more than a number means we need to add 2 to a number.

  • Let suppose the number be = x
  • Two more than the number 'x' =  x+2

  • As it is stated that two more than a number equivalent to Y.

Equivalent means something is equal to the given expression.

  • Mathematically, the 'equivalent' is represented by the symbol '='.

Thus, the English statement 'two more than a number equivalent to Y' can be algebraically represented as:

  • y = x + 2
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Match the information on the left with the appropriate equation on the right.
zaharov [31]

Answer:

See attachment below

Step-by-step explanation:

For the first option, we are given m = - 2 / 3, b = 3. This is likely in the point - slope form y = mx + b, where m = slope and b = y - intercept. Thus, the equation of the line in point - slope form given this information, should be y = - 2 / 3x + 3. It seems as if none of the following equations match this form, so let us interchange the equation a bit,

y = - 2 / 3x + 3,

y + 2 / 3x = 3,

2x + 3y = 9 - Option C

_______________________________________________________

Next we are given m = - 3 / 2, and that this line passes through the point ( 4, - 1 ). Substitute m as - 3 / 2, x as 4, y as - 1, knowing point ( 4, - 1 ), into the form y = mx + b - solving for b.

- 1 = ( - 3 / 2 )( 4 ) + b,

b = 5,

Thus the equation in point - slope form should be y = - 3 / 2x + 5. None of the choices match this, so let us again alter the equation,

y = - 3 / 2x + 5,

2y = - 3x + 10,

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_______________________________________________________

( 6, 3 ) and ( 3, 1 ) is given to lie on this line. The slope of the line should be as follows,

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3 = ( 2 / 3 )( 6 ) + b,

b = - 1,

y = 2 / 3x - 1 = Option D

Take a look at the attachment below for further help;

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