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mel-nik [20]
3 years ago
9

Investigators are combing the site of an explosion with mesh screens to collect evidence. The explosion was very large, leaving

very little evidence behind. The investigators think that they have collected a part of the original explosive. What tool could they then use to confirm this find?
Computers and Technology
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

The answer is an ion mobile spectrometer. This tool can detect explosive materials, and a bomb will naturally have explosive materials on it. Investigators will be able to say that a piece of debris with explosive materials was likely part of the original bomb.

rewona [7]3 years ago
6 0

Answer: SCANNING ELECTRON MICROSCOPY,

Explanation:Many methods are available for use in an explosion site to determine or confirm the explosive materials or bomb fragment seen or obtained from the site they include the following; SCANNING ELECTRON MICROSCOPY,

CHROMATOGRAPHY-MASS SPECTROMETRY, STEREO MICROSCOPY, CAPILLARY ELECTROPHORESIS.

SCANNING ELECTRON MICROSCOPY, is a technique used to identify or confirm a material by scanning the surface of the material using FOCUSED BEAM OF ELECTRONS IN AN ELECTRON MICROSCOPE.

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Answer:

B. How many programming statements the program contains

Explanation:

If a program is intended to be able to process large amounts of data, then the ability of the program to process larger data sets is heavily affected by

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Ashley Baker has been the webmaster for Berryhill Finance only ten days when she received an e-mail that threatened to shut down
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cyber-extortion

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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

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