All categories

2 years ago

What are the coordinates of point Q?

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

5 0

Answer:

Q (-4, -2); 2 units; Q' will be above the x-axis; 2 unites; no; yes, the y coordinates are multiplied by -1; Q' (-4, 2); R' (-2, 2), S' (1, 5), T' (-2, 5);

Step-by-step explanation:

even after a reflection over the x-axis, each points distance from the x-axis will stay the same

the x-coordinates don't change because the distance from the y-axis stays the same

the picture below shows points of Q'R'S'T', just connect the vertices

You might be interested in

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago

marshall took $36.75 to a fair. Each ticket into the fair costs X dollars. marshall bought 3 tickets. which expression represent

Sholpan [36]

Y = money left over
X = fair ticket

Y = 36.75 - 3x

7 0

3 years ago

EQUATION 10y=80. yes or no.

Darya [45]

Answer:

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

10*y-(80)=0

Pull out like factors :

10y - 80 = 10 • (y - 8)

Solve : 10 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solve : y-8 = 0

Add 8 to both sides of the equation :

y = 8

8 0

2 years ago

Read 2 more answers

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

2 years ago

What is the value of the expression 5/6 divided by 1/8

anzhelika [568]

5 $5/6 / 1/8 = 5/6 x 8/1
$

5 x 8 = 40
6 x 1 = 6

40 / 6 = 6 $4/6$ = 6 2/3

(hope I'm right & this helps you!)

7 0

3 years ago

Read 2 more answers