ASAP I NEED HELP

1 answer:

7 0

The vertex of this parabola is at (3,-2). When the x-value is 4, the y-value is 3: (4,3) is a point on the parabola. Let's use the standard equation of a parabola in vertex form:

y-k = a(x-h)^2, where (h,k) is the vertex (here (3,-2)) and (x,y): (4,3) is another point on the parabola. Since (3,-2) is the lowest point of the parabola, and (4,3) is thus higher up, we know that the parabola opens up.

Substituting the given info into the equation y-k = a(x-h)^2, we get:

3-[-2] = a(4-3)^2, or 5 = a(1)^2. Thus, a = 5, and the equation of the parabola is

y+2 = 5(x-3)^2 The coefficient of the x^2 term is thus 5.

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Solve the equation and show all work. 4|x + 1/3| = 20 <br> i'm kind of stuck hhh

34kurt

Absolute value is a function that takes some number and outputs the size of that number, regardless of the sign. By definition, $|x|=x$ if $x\ge0$ , and $|x|=-x$ if $x$ .

For example,

|2| = 2 because the input 2 is positive, so the input is unchanged;
|-3| = -(-3) = 3 because the input -3 is negative, so the sign is switched.

What this means for this problem is that there are two cases to consider:

If $x+\frac13\ge0$ , then $\left|x+\frac13\right|=x+\frac13$ , so that

$4\left(x+\dfrac13\right)=20\implies x+\dfrac13=5\implies\boxed{x=\dfrac{14}3}$

On the other hand, if $x+\frac13$ , then $\left|x+\frac13\right|=-\left(x+\frac13\right)$ , so

$-4\left(x+\dfrac13\right)=20\implies x+\dfrac13=-5\implies\boxed{x=-\dfrac{16}3}$

6 0

4 years ago

Extra help please, -7y^2-2y^2+y^3-3y-2y+5y^3-2y

nata0808 [166]

Answer:

6y^3-9y^2-7y

Step-by-step explanation:

y^3-+5t^3 - 7y^2-2y^2 - 3y-2y-2y

5 0

3 years ago

Find the value of x in the isoscleles triangle sqrt45 and altitude 3

Alisiya [41]

Answer:

$c.\hspace{3}x=12$

Step-by-step explanation:

Isosceles triangles are a type of triangles in which two of their sides have an identical length. It should be noted that the angles opposite the sides that are the same length are also the same. This means that these triangles not only have two equal sides, but also two equal angles.

You can solve this problem using different methods, I will use pythagorean theorem. First take a look at the picture I attached. As you can see:

$x=2a$