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3 years ago

NO LINKS OR ELSE YOU'LL BE REPORTED! Please give me the correct answer.Only answer if you're very good at math.

Mathematics

2 answers:

ale4655 [162]3 years ago

6 0

Answer:

it would be the last one, -3 + -1, because it wants you to go through a hoop at -4

-3 + -1 = -4

oksano4ka [1.4K]3 years ago

5 0

Answer:

the last one

Step-by-step explanation:

the last one

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Write 12/root2 + root18 in the form broot2 where b is an interger

katrin2010 [14]

$\dfrac{12}{\sqrt 2} + \sqrt{18}\\\\\\=\dfrac{12 + \sqrt{18 \times 2}}{\sqrt 2}\\\\\\=\dfrac{12+\sqrt{9 \times 4}}{\sqrt 2}\\\\\\=\dfrac{12+3 \times 2}{\sqrt 2}\\\\\\=\dfrac{18}{\sqrt 2}\\\\\\=\dfrac{18\sqrt 2}{\left(\sqrt 2\right)^2}\\\\\\=\dfrac{18\sqrt 2}2\\\\\\=9\sqrt 2$

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3 years ago

In the 30-60-90 triangle below, side s has a length of _ and side q has a length of _.

gregori [183]

Answer: F

Step-by-step explanation:

For a 30-60-90 triangle, we know that the hypotenuse is 2x. Since we know the hypotenuse is 10, we can solve for x.

2x=10

x=5

Now that we know x is 5, we can use this to solve for s and q. The side across from 30° is just x. Since we know x, s is 5.

The side across from 60° is x√3. Since we know what x is, we can just plug in. q is 5√3.

4 0

3 years ago

Please help what is x(5x6)

Rom4ik [11]

It will equal
x(5)(6)=30x

3 0

3 years ago

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Find the missing coordinate to complete the ordered-pair solution to the given linear equation.

ad-work [718]

Y=7x+1

*note that the first number is always the x.
so,

a) (0,?)
y=7(0)+1
y=1
(0,1)

b) (3,?)
y=7(3)+1
y=21+1
y=22
(3,22)

6 0

3 years ago

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URGENT Enter the values for the highlighted variables that show how to subtract the rational expressions correctly: StartFractio

Marrrta [24]

The value of the highlighted variables ave been determined a =6, b= 2 ,c= 6 , d = 2 , e = 6 , f = 6, g =1

<h3>What is an Expression ?</h3>

An expression are mathematical statement consisting of variables , constants and mathematical operators .

The given expression is

$\rm \dfrac{2}{x^2-36} - \dfrac{1}{x^2 +6x} = \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\\\= \dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{(x+6)(x+6)x}\\\\= \dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\= \dfrac{g}{x(x-6)}$

a = 6

b= 2

c= 6

d = 2

e = 6

f = 6

g =1

Therefore the value of the highlighted variables ave been determined.

To know more about Expression

brainly.com/question/14083225

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2 years ago