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Oksana_A [137]
3 years ago
9

Plz help me with this

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0

Answer: D) y = -3 sin 8x

<u>Step-by-step explanation:</u>

The given graph has an amplitude of 3 (A = 3) and a period of π/2 (B = 4).

Therefore, the equation of the graph is: y = 3 sin 8x    <em>Option A</em>

<em>Option B </em>is a reflection of <em>Option A, </em>shifted π units to the left

<em>Option C</em> is <em>Option A</em>, shifted 2π units to the right

Both <em>Options B and C</em> are equivalent to <em>Option A</em>

<em>Option D</em> is a reflection of <em>Option A</em> but since there is no horizontal shift, it cannot be equivalent to <em>Option A</em>

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D. 16 + 3y +(-3.52)

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Solve a" + 14a + 45 = 0 by factoring
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Answer:

a = -3

Step-by-step explanation:

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So, the answer is -3

Hope this helps! :)

3 0
3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
Up or down and maximum or minimum
just olya [345]
Down and maximum I think I know down is right for sure but I’m not sure about the other one
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