The surface charge density:
S(igma) = Q / A
A = 1.6 * 10^(-2) * 1.6 * 10^(-2) = 2.56 * 10^(-4) m²
The electric field: E = S / E(psilon) o
E = 0.711 * 10^^(-9) / ( 2.56 * 10 ^(-4) * 8.85 * 10 ^(-12) ) =
= 0.3138 * 10 ^6 = 3.138 * 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 * 10^5 V/m* 1.2 * 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 * 10^5 V/m * 2.40 *10^(-3) m = 753.12 V
Since he completes 10 minutes each day for five days, he completes 50 minutes.
The percentage of his total requirement would be 50/100 = 0.5 = 50%.
Answer: 12:5
Step-by-step explanation:
Step-by-step explanation:
x = 144 ( corresponding angle)
y = 180- 144 ( linear pair)
y= 36°
The answer is :23
B:34
C:56
