Solve for x. Round to the nearest tenth of a degree, if necessary.
1 answer:
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9514 1404 393
Answer:
19,463 cm²
Step-by-step explanation:
The area is given by the formula ...
A = (1/2)ij·sin(K)
Filling in the values, we find the area to be ...
A = (1/2)(270 cm)(170 cm)·sin(122°) ≈ 19,463 cm²
Area of the trapezoid:
Area of the rectangle:
4.2 x 3.1 = 13.02 cm^2
Area of each quarter circle:
We have two quarter circles:
7.54 + 7.54 = 15.08
41.65 + 13.02 + 15.08 = 69.75 cm^2
Area of the rectangle:
4.2 x 3.1 = 13.02 cm^2
Area of each quarter circle:
We have two quarter circles:
7.54 + 7.54 = 15.08
41.65 + 13.02 + 15.08 = 69.75 cm^2
The first equation, 8x - 9y = - 23
Obtain the equation in slope- intercept form
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = ( , 3) and (x₂, y₂ ) = (- 4, - 1 )
m = = (- 4)/-
=
partial equation is y = x + c
to find c substitute either of the 2 points into the partial equation
using (- 4, - 1 ), then
- 1 = - + c ⇒ c =
y = x +
← in slope- intercept form
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
rearrange the slope- intercept equation into this form
multiply through by 9
9y = 8x + 23 ( subtract 9y and 23 from both sides )
8x - 9y = - 23 in standard form