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3 years ago

What is the value of x?

Mathematics

2 answers:

gulaghasi [49]3 years ago

8 0

I believe the answer is X=15

Serggg [28]3 years ago

8 0

The scale factor is 3. So just multiply 5 by 3. it would be 15

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12. What is the length of SQ? F.5 H.13 G.9 J.17

netineya [11]

Answer:

Step-by-step explanation:

4 0

3 years ago

If the diagonals of a parallelogram are equal, then show that it is a rectangle.

Harlamova29_29 [7]

Answer:

Given: In parallelogram ABCD, AC=BD

To prove : Parallelogram ABCD is rectangle.

Proof : in △ACB and △BDA

AC=BD ∣ Given

AB=BA ∣ Common

BC=AD ∣ Opposite sides of the parallelogram ABCD

△ACB ≅△BDA∣SSS Rule

∴∠ABC=∠BAD...(1) CPCT

Again AD ∥ ∣ Opposite sides of parallelogram ABCD

AD ∥BC and the traversal AB intersects them.

∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is

180∘

From (1) and (2) ,

∠BAD=∠ABC=90∘

∴∠A=90∘ and ∠C=90∘

Parallelogram ABCD is a rectangle.

4 0

3 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago

Solve the equation 2/3 x = 6

joja [24]

Answer: x = 9

Step-by-step explanation: divide 2/3x by 2 and do that to both sides to get 1/3x = 3 then multiply by 3 to get the whole x. multiply on both sides to get x = 9.

3 0

3 years ago

Read 2 more answers

Mrs. Cleaver mixes 1.24 liters of red paint with 3 times as much blue paint to make purple paint. She pours the paint equally in

otez555 [7]

The amount of blue paint in each container is $\fbox{\begin\\\ 0.744 liters \end{minispace}}$ .

Further explanation:

The mixture mixed by Mrs. Cleaver contains 1.24 litres of red paint with 3 times blue paint to obtain purple paint.

So, the amount of blue paint is calculated as,

${3} \times {1.24}=3.72 \text { liters}$

Therefore, the total amount of paint mixture is the sum of blue paint and red paint.

$\fbox{\begin \\\begin{aligned} \text{Total paint}= 1.24+3.72\\=4.96 \text{ liters}\\\end{aligned}\\\end{minispace}}$

Now, as Mrs. Cleaver divides the paint mixture equally in 5 containers so the amount of paint in one container is calculated as,

$\boxed{\begin{aligned}\text{Amount of paint in one container}&= \dfrac{4.96}{5}\\ &=0.992 \text{ liters} \end {aligned}}$

Since amount of blue paint mixed is three times the red paint so the fraction of blue paint to the total paint is $\dfrac{3}{4}$ .

Now, as it is known that the fraction of blue paint to the total paint is $\dfrac{3}{4}$ and the amount of paint in a container is $0.992 \text{ liters}$ then the blue paint in one container is calculated as,

$\boxed{\begin{aligned}\text{Blue paint in one container} =\dfrac{3}{4} \times 0.992\\=0.248 \text{ liters}\end{aligned}}$

Thus, the amount of blue paint in each of the five containers is $\fbox{\begin\\\ 0.744 liters \end{minispace}}$ .

Learn more:

1. To solve one variable linear equation brainly.com/question/1682776

2. Linear equation application brainly.com/question/2479097

3. Composite functions brainly.com/question/2142762

Answer details

Grade: Middle school

Subject: Mathematics

Chapter: Mixtures and ratios

Keywords: mixture, paint, red paint, blue paint, Mrs. Cleaver, purple paint, fraction, each container, five containers, divides, times, equally divide, mixes, liters.

3 0

3 years ago

Read 2 more answers