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viva [34]
3 years ago
10

If a flower bed has the shape of a rectangle 7 yards long and 3 yards wide what is the area in square feet

Mathematics
1 answer:
vichka [17]3 years ago
8 0
I believe it is 189 square feet
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Based on the graph shown to the right, whose phones cost varies directly with the amount of time spent talking?
Lena [83]

Answer:

B

Step-by-step explanation:

Given 2 quantities that vary directly, then the graph must pass through the origin.

Nikiya's graph is the only one to do this ⇒ B



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Rory has 4 pounds of ground beef to make meatballs. He uses 3/8 pound per meatball to make 9 meatballs. How many 1/8-pound meatb
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0.125

Step-by-step explanation:

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Suppose you have 100 ft of string to rope off a rectangular section for a bake sale at a school Fair. The function A=x^2+50x giv
cupoosta [38]

Answer:

Therefore the width is 25 feet for getting maximum area.

The maximum area of the rectangle is 625 square feet.

Therefore the range is 0≤A≤625.

Step-by-step explanation:

Given function is

A = - x²+50x

We know that ,

If y = ax²+bx+c

For the maximum x=-\frac{b}{2a}

Here a = -1 , b= 50 and c=0

Therefore the width x= -\frac{50}{2.(-1)} = 25

Therefore the width is 25 feet for getting maximum area.

The maximum area =[ -(25)²+50.25] square feet

                                 = 625 square feet

The area can not be negative and maximum area is 625 square feet.

Therefore the range is 0≤A≤625.

5 0
3 years ago
A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about
Radda [10]

Answer:

f(2)=5

f(5)=33

Step-by-step explanation:

The given formula, that recursively defines the sequence is

f(1) = 3 \\ f(n + 1) = 2f(n) - 1

When n=1, we obtain;

f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5

When n=2, we get:

f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9

When n=3,

f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17

When n=4

f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33

When n=5,

f(6) = 65

4 0
3 years ago
Prove that 1/sec0-tan0= sec0+tan0
Leviafan [203]

Answer:

Step-by-step explanation:

\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}

7 0
2 years ago
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