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2 years ago

Which is the better buy 4 muffins for 0.85 or 1dozen muffins for 2.50

Mathematics

2 answers:

Brrunno [24]2 years ago

7 0

Answer:

the 1 dozen for $2.50

Step-by-step explanation:

there are 1 in a dozen so you do 2.50 divided by 12

kherson [118]2 years ago

3 0

The dozen is 20cents per muffin while the 4 is 21 cents per muffin

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olga_2 [115]

You first add up how many erasers there are in the bag so there are 20 and then you check how many purple erasers there are and so there are 5 and so the answer is 5/20 or 1/4 which is 0.25 as a decimal and if you do probability the answer has to be in between o and 1 and so 0.25 is in between 0 and 1 so it should be correct

3 0

3 years ago

Read 2 more answers

1)A fish tank has a volume of 520 in. it is emptied at a constant rate of 10 cubic inches every minute. Which equation represent

disa [49]

Answer:

v=520 -10t

Step-by-step explanation:

the rate of decrease is given a variable to calculate the rate of change. v is represented by 520 - the number of minutes.

4 0

2 years ago

If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)

Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

$\log_dabc=\log_da+\log_db+\log_dc$

Then using the change of base formula, we can derive the relationship

$\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}$

This immediately tells us that

$\log_dc=\dfrac1{\log_cd}=\dfrac12$

Notice that none of $a,b,c,d$ can be equal to 1. This is because

$\log_1x=y\implies1^{\log_1x}=1^y\implies x=1$

for any choice of $y$ . This means we can safely do the following without worrying about division by 0.

$\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}$

so that

$\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23$

Similarly,

$\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}$

so that

$\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34$

So we end up with

$\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}$

###

Another way to do this:

$\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}$

$\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}$

$\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12$

Then

$abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}$

So we have

$\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}$

4 0

2 years ago

-32x + 45 – 7 (2x – 9) = 101

Evgesh-ka [11]

Answer:

$x = \frac{7}{46}$

Step-by-step explanation:

-32x+45-7(2x-9)=101

parenthesis first

-32x+45-14x+63=101

just combine like terms

-46x+108=101

minus 108 both sides

-46x= -7

answer is x 7 over 46

5 0

3 years ago

Read 2 more answers

A university has 750 female students and 2250 male students. Thirty per cent of female students study chemistry and 60% of male

UNO [17]

Answer:

1/7 or 14.3%

Step-by-step explanation:

30% of 750 = 225 (females who study chemistry)

60% of 2250 = 1350 (males who study chemistry)

1575 = total students studying chemistry

P (female chemistry student) = 225/1575 = 1/7 (simplified)

1/7 = 14.3%

7 0

2 years ago