4
put it in a calculator and include all the parentheses
Answer:
The probability that a call last between 4.2 and 4.9 minutes is 0.4599
Step-by-step explanation:
Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula

We will use
, the cummulative distribution function of W. The values of
are well known and the can be found in the attached file

We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599
Answer:
15z - 9p
Step-by-step explanation:
7z - 9p + 9z - z
=7z - 9p +8z
= -9p + 15z or 15z - 9p Answer
Hope this helps!
I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus