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2 years ago

Find two consecutive whole numbers that 58 lies between?

Mathematics

2 answers:

VladimirAG [237]2 years ago

8 0

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Step-by-step explanation:

Ne4ueva [31]2 years ago

6 0

Answer:

No such pair of integers. Hence, no solution.

Step-by-step explanation:

As the only factors of

58 are { 1 , 2 , 29 , 58 } , there are no two consecutive integers whose product is 58 .

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natulia [17]

Answer:

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Step-by-step explanation:

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A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia

iogann1982 [59]

$\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\$

$\bf P=182e^{kt}\qquad 
\begin{cases}
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t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}$

what's the population in 2004? well, from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004

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Step-by-step explanation:

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