The radius of a circle is half of the diameter
10.) (6/5)= 1.2
1.2/2=.6
The radius of the circle in question 10 is .6 or 1/2 inch
11.) because x (diameter) is not defined in this problem. We can't solve directly for x, but we know the radius is half of the diameter
so we can say
r= 1/2x
Let z = 3x+2. Then, by substitution, your equation is
.. z^2 +7z -8 = 0
_____
This equation can be factored as
.. (z +8)(z -1) = 0
.. x = -8 or +1
Then
.. 3x +2 = -8 or +1
.. 3x = -10 or -1
.. x = -10/3 or -1/3
The value of k is -6
Step-by-step explanation:
The general form of the quadratic equation is y = ax² + bx + c
- The roots of the equation is the values of x when y = 0
- ax² + bx + c = 0, is used to find the roots
∵ 2x² + 11x = -k
- Add k to both sides
∴ 2x² + 11x + k = 0
∵ The roots of the quadratic equations is the values of x when y = 0
∵
is a root of the equation
- Substitute x by
in the equation above to find k
∵ 2(
)² + 11(
) + k = 0
∴ 2(
) +
+ k = 0
∴
+
+ k = 0
- Add the like terms
∵
+
=
= 6
∴ 6 + k = 0
- Subtract 6 from both sides
∴ k = -6
The value of k is -6
Learn more:
You can learn more about the quadratic equations in brainly.com/question/8196933
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Answer:
The maximum profit is reached with 4 deluxe units and 6 economy units.
Step-by-step explanation:
This is a linear programming problem.
We have to optimize a function (maximize profits). This function is given by:

being D: number of deluxe units, and E: number of economy units.
The restrictions are:
- Assembly hours: 
- Paint hours: 
Also, both quantities have to be positive:

We can solve graphically, but we can evaluate the points (D,E) where 2 or more restrictions are saturated (we know that one of this points we will have the maximum profit)

The maximum profit is reached with 4 deluxe units and 6 economy units.
Hmm, I'd say it's the first option.