All categories

3 years ago

ASAP! I NEED THIS DONE AS QUICKLY AS POSSIBLE WITH WORKING OUT

Mathematics

1 answer:

matrenka [14]3 years ago

3 0

Yo sup??

To find velocity just differentiate the function r once wrt to t

v=dr/dt=(9t^2-1)i+(4t+2)j)

and to find acceleration differentiate v wrt to t

a=dv/dt=18ti+4j

Hope this helps.

You might be interested in

The other side is 25, but im not sure what sin B is

ruslelena [56]

9514 1404 393

Answer:

sin B = 24/25

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

Sin = Opposite/Hypotenuse

The side opposite angle B is the side AC. Its length is shown as 24. You have correctly said the hypotenuse (AB) is 25, so you have ...

sin(B) = AC/AB

sin(B) = 24/25

3 0

3 years ago

Luke is building a bike ramp. The ramp is going to be 3 feet tall on the high end and 6 feet long. How long is the base of the r

eimsori [14]

Answer: 5.1961

Step-by-step explanation: I believe you would use the Pythagorean’s theorem, since it’s a problem about a ramp, always draw pictures for word problems. So you would plug your numbers in the formula and solve. 3 squared plus B squared (that’s what we are trying to find so its a variable) equals 6 squared. Then you square and it becomes 9 + b2= 36, subtract 9 on both sides, b2=27, then square root on both sides to get 5.1961. Hopefully that’s right. :)

7 0

4 years ago

Q20-23 with steps pls

just olya [345]

20: Let $x$ be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

$\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30$

Rearrange the left hand side as

$\dfrac{4x-3x}{24}=30$

And multiply both sides by 24 to get

$x=720$

21: Let $M$ and $J$ be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

$M=3J+11$

If they both get 9 more marbles, Mike will have $M+9$ marbles, and Judy will have $J+9$ marbles. So, we have

$M+J+18=93 \iff M+J=75 \iff M=75-J$

Plug this value in the first equation and we have

$75-J=3J+11 \iff 4J=64 \iff J=16$

And we deduce

$M=16\cdot 3 + 11=59$

So, the difference is

$M-J=59-16=43$

22: Let $x,y,z$ be the number of $10, $20 and $50 coupon, respectively. We're given:

$\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}
We can write the third equation by substituting the expressions for x and z:
[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38$