<img src="https://tex.z-dn.net/?f=Expand%20%24%28a%20%2B%202%29%283a%5E2%20%2B%2012%29%28a%20-%202%29.%24" id="TexFormula1" titl

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3 years ago

e="Expand $(a + 2)(3a^2 + 12)(a - 2).$" alt="Expand $(a + 2)(3a^2 + 12)(a - 2).$" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

sashaice [31]3 years ago

5 0

Answer:

3 $a^{4}$ - 48

Step-by-step explanation:

Given

(a + 2)(3a² + 12)(a - 2)

= (a + 2)(a - 2)(3a² + 12) ← expand the first pair of parenthesis using FOIL

=(a² - 4)(3a² + 12) ← expand using FOIL

= 3 $a^{4}$ + 12a² - 12a² - 48 ← collect like terms

= 3 $a^{4}$ - 48

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3 years ago

Anarel [89]

*Correct Question:

Based on the similar triangles shown below, Theodore claims that ∆TUV is transformed to ∆WXY with a scale factor of 3/2. Is Theodore correct?

A. Yes, the triangles are similar with a scale factor of 3/2.

B. No, the triangles are similar with a scale factor of 2/1.

C. No, the triangles are similar with a scale factor of 2/3.

D. No, the triangles are similar with a scale factor of 4/3.

Answer:

C. No, the triangles are similar with a scale factor of 2/3.

Step-by-step explanation:

∆TUV is the original triangle. After transformation, the size reduced to give us ∆WXY. This means ∆TUV was reduced by a scale factor to give ∆WXY. The scale factor should be a fraction, suggesting, the original size of the ∆ was reduced upon transformation.

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If you multiply the side length of ∆TUV by ⅔, you'd get side length of ∆WXY.

So, Theodore is wrong.

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3 years ago