What is the equation of a parabola that has a vertex at ( 0,4 ) and passes through points ( 2,0 )?
1 answer:
Answer:
<u>y = -x² + 4</u>
Step-by-step explanation:
The equation of the parabola in the vertex form is:
y = a (x-h)² + k
Where: (h,k) the coordinates of the vertex & a is a multiplier
The parabola has a vertex at ( 0,4 )
So, h = 0 , k = 4
∴ y = a (x-0)² + 4
∴ y = a x² + 4
The parabola passes through points ( 2,0 )
∴ 0 = a 2² + 4
∴ 4 a = -4 ⇒ a = -4/4 = -1
∴ y = -x² + 4
So, the equation of a parabola that has a vertex at ( 0,4 ) and passes through points ( 2,0 ) is <u>y = -x² + 4</u>
See the attached figure.
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The equation (1) is divided by 2 to create new equivalent system of equations.
Step-by-step explanation:
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Considering 8y instead of 8 in eq(1)
We need to identify what action was completed to create this new equivalent system of equations?
Comparing given equations we came to know that equation(1) is divided by 2 to get the new equation i.e
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So, The equation (1) is divided by 2 to create new equivalent system of equations.
Keywords:System of Equation
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