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Alborosie
3 years ago
6

What is the nearest tenth of 4.12311

Mathematics
2 answers:
svp [43]3 years ago
3 0
Answer:

The nearest tenth of 4.12311 is 4.1
marusya05 [52]3 years ago
3 0
The nearest tenth is 4.1
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A . 5 - 4/8<br> B. -1/8 - 1/4<br> C. -1/4 - (-1/8)<br> or D. -1/6 + (-5/24)
xenn [34]

Answer:

letter ( D ).

1/6 + ( - 5 / 2 4 )

7 0
2 years ago
PLEASE HELP!!!!!! 4.13×10^-8×0.04×10^5?!
vladimir2022 [97]
Try solving it on your own
you must factor the integers
0.00017 is the answer though
4 0
3 years ago
A bicycle tire is 28 inches in diameter.Approximately how far does the bicycle move forward each time the wheel goes around?(use
Debora [2.8K]

Answer:

88 Inches

Step-by-step explanation:

For any bicycle tire of a given diameter, the approximate distance moved by the bicycle each time the wheel goes around is determined by the circumference of the circular wheel.

Since the diameter =28 Inches

Circumference =\pi d =\frac{22}{7}X28 =88$ Inches

The bicycle moves 88 Inches forward each time the wheel goes around.

4 0
3 years ago
What is 26/57= 849/5x
Leto [7]

\frac{26}{57}=\frac{849}{5}x \\ \\ x=\left(\frac{26}{57} \right) \left(\frac{5}{849} \right) \\ \\ x=\boxed{130/48393}

4 0
1 year ago
What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanB = \dfrac{AD}{BD}

Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

5 0
2 years ago
Read 2 more answers
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