All categories

3 years ago

Hey please help me please help please

Mathematics

1 answer:

Airida [17]3 years ago

4 0

a) metres to centimetres :

multiply length by 100

b) metres to millimetres:

multiply length by 1000

c) kilograms to grams:

multiply the mass value by 1000

d) litres to millilitres :

multiply volume by 1000

a) 3 m = 3× 100 = 300 cm

b) 28 cm = 28 × 10 = 280 mm

c) 2.4 km = 2.4 × 1000

= 24 × 10^-1 × 10^3

= 24 × 10^2 =2400 m

d) 485 mm =485 / 10

= 485 / 10 ^1

= 485 × 10 ^-1

= 48.5 cm

e) 35 cm = 35 / 100

= 35 /10^2

= 35 × 10 ^ -2

= 0.35 m

f) 2.4 m = 2.4 / 1000

= 24 × 10 ^-1 / 10^3

= 24 × 10^-1 × 10 ^-3

= 24 × 10 ^ -4

= 0.0024 km

g) 2495 mm = 2495 /1000

= 2495 /10^ 3

= 2495 × 10 ^-3

=2.495 m

You might be interested in

Are the given angles complementary, supplementary, or neither? ∠VYW and ∠WYX A. complementary B. supplementary C. neither

Yuki888 [10]

Answer is <span> A. complementary

sum of those 2 angles = 90</span>

5 0

4 years ago

The diameters of ball bearings are distributed normally. The mean diameter is 130 millimeters and the variance is 9. Find the pr

Crank

Answer:

0.0478

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 135 mm

μ is the population mean = 130 mm

σ is the population standard deviation.

We are given variance = 9

Standard deviation = √variance = √9 = 3

Hence

z = 135 - 130/3

z = 1.66667

Probability value from Z-Table:

P(x<135) = 0.95221

P(x>135) = 1 - P(x<135) = 0.04779

Approximately to 4decimal places = 0.0478

8 0

3 years ago

Which function models the sum?

OLEGan [10]

I can’t see it I just see black

8 0

3 years ago

A factory fills bottles with a beverage, and each bottle is supposed to contain 500\text{ mL}500 mL500, start text, space, m, L,

Delicious77 [7]

Answer:

The test statistic for Norah's test is $t = -2$

Step-by-step explanation:

Norah is in charge of a quality control test that involves measuring the amounts in a sample of bottles to see if the sample mean amount is significantly different than 500 ml.

This means that at the null hypothesis we test if the sample mean is 500 ml, that is:

$H_0: \mu = 500$

At the alternate hypothesis, we test if it is differente than 500 ml, that is:

$H_a: \mu \neq 500$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.