441 is odd, so we can't divide it by 2.
Since the sum of its digits is 
, which is divisible by 3, we can divide 441 by 3, and we have
Which is still divisible by 3, because 
. We have
49 is not divisible by 3 anymore, nor by 5 (it doesn't end with 0 or 5).
It is divisible by 7 though, we have
and finally,
So, the factorization of 441 is
Consider the following expanded powers of (a + b)n, where a + b is any binomial and n is a whole number. Look for patterns.
Each expansion is a polynomial. There are some patterns to be noted.
1. There is one more term than the power of the exponent, n. That is, there are terms in the expansion of (a + b)n.
2. In each term, the sum of the exponents is n, the power to which the binomial is raised.
3. The exponents of a start with n, the power of the binomial, and decrease to 0. The last term has no factor of a. The first term has no factor of b, so powers of b start with 0 and increase to n.
4. The coefficients start at 1 and increase through certain values about "half"-way and then decrease through these same values back to 1.
Answer:
b)
Step-by-step explanation:
b) set up equations so they are equal to each other,
this is when f(x)=g(x) so our approximation was close.
c)solving it graphically is nearly impossible because the solution can be any value around the intersection. only way to be sure is to solve it symbolically.
Answer:
=20s³+50s²+32s+6
Step-by-step explanation:
We multiply each of the term in the initial expression by the the second expression as follows:
4s(5s²+10s+3)+2(5s²+10s+3)
=20s³+40s²+12s+10s²+20s+6
Collect like terms together.
=20s³+50s²+32s+6
