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tresset_1 [31]
2 years ago
7

What is the center of a circle represented by the equation (x 9)2 (y−6)2=102? (−9,6) (−6,9) (6,−9) (9,−6)

Mathematics
2 answers:
solong [7]2 years ago
4 0

Answer:

A. (-9, 6)

Step-by-step explanation:

i did it B)

Korvikt [17]2 years ago
3 0

The center of the circle (x + 9)² + (y − 6)² = 10² is at (-9, 6) and the radius of the circle is 10 units.

<h3>What is a circle?</h3>

It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

The equation of the circle is given as

(x + 9)² + (y − 6)² = 10²

Then the center of the circle is at (-9, 6) and the radius of the circle is 10 units.

More about the circle link is given below.

brainly.com/question/11833983

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Pleaseeee help w these math questions! please show work!!!<br><br> 50 points
Schach [20]

9. You need an exact answer. So I will give you it but I'll also give you an approximation because it might help you understand it more.

Because we know the cosine fo theta, we can evaluate the inverse cosine of -2/3 first to find theta.

sin^{-1}(-2/3) = 131.81° approx.

Because 131.81° is in the second quadrant its third quadrant partner is 228.19°. Which would make the sine 0.75 approximately.

But we need an exact answer I suppose so which is this disgusting mess...sin(2\pi -cos^{-1}(\frac{-2}{3})). I know it looks scary but it is basically  all the steps we just did but without evaluating anything.

This can be simplified using: sin(x− y) = sinxcosy−cosxsiny

To... -sin(cos^{-1}(\frac{-2}{3}))

answer: -sin(cos^{-1}(\frac{-2}{3}))

10. Okay. So because we have a point we can say that...

θ = tan^{-1}(-9/11)

sin(θ) = +sin(tan^{-1}(-9/11))

11. arcsin(-0.37) = sin^{-1}(-0.37) = -21.72°+2kπ or 201.72°+2kπ approx. where k has to be an integer

answer: idk if you want one or more solutions so I gave you them all.

12. arccos(-√3/2) = cos^{-1}(\frac{-\sqrt{3} }{2}) = \frac{5\pi }{6}+2k\pi, \frac{7\pi }{6}+2k\pi

Remember that "k" must be an integer.

answer: 5π/6

6 0
3 years ago
what is the distance between the points (4, 5) and (10, 13) on a coordinte plane a. 12 units b. 8 units c. 10 units d. 14 units
qaws [65]

Answer:

<h2>10 units</h2>

Option C is the correct option

Step-by-step explanation:

Let the points be A and B

A ( 4 , 5 ) ------> ( x1 , y1 )

B ( 10 , 13 ) ------> ( x2 , y2 )

Now, let's find the distance between these points:

\sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} }

plug the values

= \:  \sqrt{(10 - 4) ^{2} +  {(13 - 5)}^{2}  }

Calculate the difference

=  \sqrt{ {(6)}^{2} +  {(8)}^{2}  }

Evaluate the power

=  \sqrt{36 + 64}

Add the numbers

=  \sqrt{100}

Write the number in exponential form with. base of 10

=  \sqrt{ {(10)}^{2} }

Reduce the index of the radical and exponent with 2

= 10 \: units

Hope this helps..

Best regards!!

7 0
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Gwar [14]

Answer:

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Evgen [1.6K]

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Step-by-step explanation:

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