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klio [65]
3 years ago
8

|-6|-|7-41|? A. -40 B. -28 C. 28 D. 40 E. 54

Mathematics
1 answer:
Nina [5.8K]3 years ago
8 0

Answer:

the answer to this question is b. -28

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Which statement is true? 1) The y-value of Function A when x=-1 is greater than the y-value of Function B when x=-1. 2) The y-va
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The answer is 2 I believe
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A lighthouse is built on an exposed reef, 4.5 miles off-shore. The shoreline is perfectly straight, and a town is located 6 mile
Alisiya [41]

Answer: 3.94 hours

Step-by-step explanation:

From the question, the following parameters are given:

Distance offshore = 4.5 miles

Distance downshore = 6 miles

Speed when running = 3.4 mph

Speed with boat = 1.8 mph

distance of boat rowing = sqrt(4.5^2 + x^2)

Where

Speed = distance/time

Time = distance/speed

Time = distance of boat rowing/1.8

distance of running = 6 - x

Time = (6-x)/3.4

total travel time

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

dt/dx = x/(1.8×sqrt(4.5^2 + x^2) - 1/3.4

d^2t/dx^2 = +ve at any x

x is at its minimum when dt/dx=0

x/(1.8×sqrt(4.5^2 + x^2) = 1/3.4

x = 6/sqrt(253) × 4.5 = 1.697 miles

Substitute x in

t = sqrt(4.5^2 + x^2)/1.8 + (6 - x)/3.4

We obtaine

t = sqrt(4.5^2 + 1.697^2)/1.8 + (6 - 1.69)/3.4

t = 2.672+ 1.266 = 3.94 hours

7 0
3 years ago
The value of x satisfying both the equations 4x – 5 = y and 2x – y = 3, when y = -1 is
schepotkina [342]

Answer:

x = 1

Step-by-step explanation:

4x-5=y

4x-5= -1

4x = -1+5

4x=4

x=1

2x-y=3

2x-(-1)=3

2x+1=3

2x= 3-1

2x= 2

x=1

since the two answers for x are the same therefore:

x = 1

4 0
3 years ago
The value of 9 in 90,000 is how many times the value of 9
Semmy [17]
The value is 10,000!!!
8 0
3 years ago
The dimensions of a rectangle box are consecutive integers. If the box has volume of 13,800 cubic centimeters, what are its dime
klasskru [66]
Three consecutive integers are x, x+1, x+2.
The volume of a rectangular box is the product of its three dimensions. The volume is 138000 cm³.

x(x+1)(x+2)=13800 \\
(x^2+x)(x+2)=13800 \\
x^3+2x^2+x^2+2x=13800 \\
x^3+3x^2+2x-13800=0 \\
x^3-23x^2+26x^2-598x+600x-13800=0 \\
x^2(x-23)+26x(x-23)+600(x-23)=0 \\
(x^2+26x+600)(x-23)=0 \\ 
x^2+26x+600=0 \ \lor \ x-23=0 \\ \\
1. \\
x^2+26x+600=0 \\ \\
a=1 \\ b=26 \\ c=600 \\ \Delta=b^2-4ac=26^2-4 \times 1 \times 600=676-2400=-1724 \\
\hbox{the discriminant is less than 0 so there are no real solutions} \\ \\
2. \\
x-23=0 \\
x=23 \\ \\
x+1=23+1 =24 \\ \\
x+2=23+2=25

The dimensions of the box are 23 cm x 24 cm x 25 cm.
5 0
3 years ago
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