For this case, the first thing we must do is define variables:
x: number of quarters
y: number of nickels
We now write the system of equations:
x + y = 68
0.25x + 0.05y = 13.40
Solving the system we have:
x = 50
y = 18
Answer:
they have:
quarters = 50
nickels = 18
Answer:
1)
82.5 - <u>8</u><u>2</u><u>.</u><u>5</u> + 2x = 338.5 - <u>8</u><u>2</u><u>.</u><u>5</u>
<u>2</u>x = <u>2</u><u>5</u><u>6</u>
2)
2x ÷ <u>2</u> = 256 ÷ <u>2</u>
x = <u>1</u><u>2</u><u>8</u>
Step-by-step explanation:
1)
In order to get rid 82.5, you have to substract the same value on both side to get a 0 value.
2)
In order to find the value of x, you have to divide the value that is sticked with x which is 2. As you divide 2 by 2, you will get 1 as a single value of x so you have to divide 2 to both side too.
Answer:4200
Step-by-step explanation:
Answer:
The eastbound train travels at 92 mph and the westbound train travels at 96 mph.
Step-by-step explanation:
We know that Velocity = distance / time
If the eastbound train travels at x miles per hour, the westbound train travels at x + 4 mph.
After 3.5 hours, they are 658 miles apart. If we solve for distance the formula given above we have: Distance = velocity x time. We have that the total distance between both trains is 658 miles.
Substituting the values of the problem and solving for x we have

Thus, the eastbound train travels at 92 mph and the westbound train travels at 96 mph.
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>x^</em><em>2</em><em>-</em><em>1</em><em>.</em>
<em>EXPLANATION</em><em>:</em>
<em>To</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>polynomial</em><em>,</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>each</em><em> </em><em>term</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>whole</em><em> </em><em>number</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>