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Tatiana [17]
3 years ago
14

Consider the following system of equations:

Mathematics
2 answers:
mars1129 [50]3 years ago
8 0

Answer:2

Step-by-step explanation:

horrorfan [7]3 years ago
6 0

Answer:

(x = -11 and y = 56) or (x = 1 and y = -4)

Step-by-step explanation:

The equation of the parabola is 10 + y = 5x + x² ........(1)

And 5x + y = 1 ....... (2) is the straight line.

We have to find solutions to equations (1) and (2).

Now, solving equations (1) and (2) we get, 10 + (1 - 5x) = 5x + x²

⇒ 11 - 5x = 5x +x²

⇒x² + 10x - 11 = 0

⇒ (x + 11) (x - 1) = 0

Hence, x = -11 or x = 1

Now, from equation (2),  

y = 1 - 5x = 1 - 5(-11) = 56 {When x = -11}

And, y = 1 - 5(1) = -4 (When x = 1}

Therefore, the solution of the system are (x = -11 and y = 56) or (x = 1 and y = -4) (Answer)

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Which are solutions of the equation 4x2 – 7x = 3x + 24? Check all that apply.
SCORPION-xisa [38]

Answer:

{-3/2, 4}

Step-by-step explanation:

Use synthetic division here.  If the remainder is 0, then the divisor is a root or solution.

Here we have x = -4.  Perform the synthetic division as follows:

-4       4     -10    -24

                 -16     108

------------------------------

          4      -26     84              The remainder is 84, which tells us -4 is NOT

                                                a root/solution.

Try -3/2 as divisor this time:

-3/2    4     -10    -24

                   -6    24

------------------------------

          4      -16       0            Remainder is 0, so -3/2 is a solution

Show in the same manner that 4 is a solution also.  Or determine whether x - 4 satisfies 4x - 16 = 0 (it does).

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C is the correct answer homie
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Step-by-step explanation:

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