Question

how many grams of ammonium carbonate are needed to decompose in order to produce 6.52 g of carbon dioxide?

Answer 1

Answer:

= 14.24g of $(NH4)_{2}CO_{3}$ is required.

Explanation:

Reaction equation:

$(NH4)_{2}CO_{3}$ → $2NH_{3} + CO_{2} + H_{2} O$

Mole ratio of ammonium carbonate to carbon dioxide is 1:1

1 mole of CO2 - 44g

?? mole of CO2 - 6.52g

= 6.52/44 = 0.148 moles was produced from this experiment.

Therefore, if 1 mole of $(NH4)_{2}CO_{3}$ - 96.09 g

0.148 mol of $(NH4)_{2}CO_{3}$ --  ?? g

=0.148 × 96.09

= 14.24g of $(NH4)_{2}CO_{3}$ is required.