Answer:
<em>When molecular hydrogen (H2) and oxygen (O2) are combined and allowed to react together, energy is released and the molecules of hydrogen and oxygen can combine to form either water or hydrogen peroxide.</em>
Answer:
The total mass of glucose and oxygen is equal to the total mass of carbon dioxide and water.
Explanation:
:)
Its 2-chlorobutanal
hope that helps
At the beginning there was just
1 mole of hydrogen and
1 mole of iodin.
The reaction goes:
![H_2+I_2\Rightarrow\ 2HI](https://tex.z-dn.net/?f=H_2%2BI_2%5CRightarrow%5C%202HI)
One mole of hydrogen goes with one mole of iodin, creating
2 moles of product.
If 0.8 of hydrogen remaind, it means that
1-0.8=0.2 reacted.
So:
1 mole H2 react with 1 mole I2 creating 2 moles of products.
So 0.2 of hydrogen reacted with 0.2 mole of iodin creating 0.4 moles.
Answer:
The different magnetic shielding effects of the carbonyl double bond in CH0, the CH₂ (a) and CH₂ (b) protons show different chemical shifts
Because the degree of shielding depends on electron density round the proton, the neighboring carbonyl group will increase this density in geranial form.
Now in CH₂ the electron density is increased around CH₂ (a) protons in neral form due to the carbonyl group, and thus it has a lower z values than the corresponding geranial form.
In the case of CH₃ (b) protons. thus they have lower z values and higher chemical shift than the corresponding nera form.
Explanation:
Solution
Due to the different magnetic shielding effects of the carbonyl double bond in CH0, the CH₂ (a) and CH₂ (b) protons show different chemical shifts.
Since the degree of shielding depends on electron density round the proton, the neighboring carbonyl group will increase this density in geranial form more in case of CH₃ (b) protons. thus they have lower z values and higher chemical shift than the equivalent nera form.
Similarly, the electron density is increased around CH₂ (a) protons in neral form due to the carbonyl group, and thus it has a lower z values than the equivalent geranial form.