Answer: The final molarity of the diluted oxalic acid solution is 0.0032 M
Explanation:
Molarity: It is defined as the number of moles of solute present per liter of the solution.
Formula used :
where,
n= moles of solute
Moles=
= volume of solution in ml
To calculate the final molarity of the diluted oxalic acid solution
where,
are the molarity and volume of concentrated oxalic acid solution.
are the molarity and volume of diluted oxalic acid solution.
We are given:
Putting values in above equation, we get:
Thus the final molarity of the diluted oxalic acid solution is 0.0032 M
Answer:
Answer refer to the above attachment .
Bcoz some words are unable to answer .
Answer:
Esterification reaction
Explanation:
When we have to go from an acid to an ester we can use the <u>esterification reaction</u>. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).
In this case, we need the <u>methyl ester</u>, therefore we have to choose the <u>appropriate alcohol</u>, so we have to use the <u>methanol</u> as reactive if we have to produce the methyl ester.
Answer is: it takes 116,8 seconds to fall to one-sixteenth of its initial value
<span>
The half-life for the chemical reaction is 29,2 s and is
independent of initial concentration.
c</span>₀
- initial concentration the reactant.
c - concentration of the reactant remaining
at time.
t = 29,2 s.<span>
First calculate the rate constant k:
k = 0,693 ÷ t = 0,693 ÷ 29,2 s</span> = 0,0237 1/s.<span>
ln(c/c</span>₀) = -k·t₁.<span>
ln(1/16 </span>÷ 1) = -0,0237 1/s ·
t₁.
t₁ = 116,8 s.
