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maria [59]
3 years ago
13

The numbers of bags of crisps sold per day in a general shop was recorded over 13 days.

Mathematics
1 answer:
Alona [7]3 years ago
6 0

I just figured it out so I’ll answer it on this account lol.

Q1 = 32, Q2 = 45, Q3 = 52

Interquartile range = 52 - 32 = 20

Range = 68 - 21 = 47

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Point A is the midpoint of side XZ and point B is the midpoint of side YZ. Triangle X Y Z is cut by line segment A B. Point A is
AveGali [126]

Answer:

<h3>B. 4units</h3>

Step-by-step explanation:

Find the diagram attached. The diagram is a similar triangle.

From the diagram, XZ/XY = CA/AB

Given XZ = 2x-2+2x-2 = 4x-4

XY =5x-7

CA = 2x-2

AB= x+1

On substituting this parameters into the formula to get x first

4x-4/5x-7 = 2x-2/x+1

cross multiply

(4x-4)(x+1) = 5x-7(2x-2)

open the parenthesis

4x²+4x-4x-4 = 10x²-10x-14x+14

4x²-4 = 10x²-24x+14

10x²-4x²-24x+14+4 = 0

6x²-24x+18 = 0

x²-4x+3 = 0

x²-3x-x+3 = 0

x(x-3)-1(x-3)  =0

(x-3)(x-1) = 0

x = 3 and 1

Next is to get length AX.

Given AX = 2x-2

Substitute x = 3 into the expression

AX = 2(3)-2

AX = 6-2

AX = 4 units

Hence the measure of length AX is 4 units

4 0
3 years ago
If you make $20 per hour, how many hours did you work if you earned
mestny [16]

Answer: 8 hours

If you are making 8 dollars an hur you need to go find another job

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
192 rounded to nearest tenth?
Andrews [41]

There is no TENTH in 192 so 192 rounded to the nearest TENTH is 192.


If you meant TEN then 192 rounded to the nearest TEN is 190.

Good Luck!

5 0
3 years ago
Read 2 more answers
.........................
Zigmanuir [339]

Answer:

A

Step-by-step explanation:

given 3xy + 4yz + 8xz = 10

subtract 8xz from both sides leaving the terms in y together

3xy + 4yz = 10 - 8xz

take out the common factor y on the left side

y(3x + 4z) = 10 - 8xz

divide both sides by (3x + 4z)

y = \frac{10-8xz}{3x+4z} → A


5 0
3 years ago
A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
3 years ago
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