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pishuonlain [190]
3 years ago
10

How do I write 76543 to the -4 power in simplest form?

Mathematics
1 answer:
Reika [66]3 years ago
4 0

<u>Answer:</u>

<u />

So, I don't know how other teachers taught you, but I have a trick.

<u>Step-by-step explanation:</u>

<u />

Step 1:

Solve 76543^{4}

76543^{4} = 34325898917194100000

Step 2:

Now put 34325898917194100000 under 1, like this:

\frac{1}{34325898917194100000}

<em>Note: Whenever you have a negative power, the result of the exponent will always be a fraction under 1.</em>

<em />

Step 3:

Add the negative:

\frac{1}{34325898917194100000} becomes:

-\frac{1}{34325898917194100000}

Your answer is -\frac{1}{34325898917194100000}

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

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What is the surfsce area of the prism with 12 cm 11 cm and 10,cm
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Answer:

Step-by-step explanation:

The surface area of a rectangular prism is

A=2(xy+xz+yz). where x,y,z are its dimensions, in this case

A=2(12(11)+12(10)+11(10))

A=2(132+120+110)

A=2(362)

A=724 cm^2

8 0
3 years ago
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If sin (A+B)=1 and tan (A-B)=1/sqroot 3<br><br> are acute angles. find out the value of A and B​
Nataliya [291]

Answer:

A = 60° , B = 30°

Step-by-step explanation:

sin(A+B ) = 1\\\\\  \  \ (A + B) \  = \ \ sin^{-1} 1\\\\A + B = 90^\circ  --(1)\\\\ \ tan (A - B) = \frac{1}{\sqrt{3}}\\\\(A-B) = tan^{-1}\frac{1}{\sqrt3}}\\\\A - B =  30^\circ --(2)\\\\ (1)  + (2) => 2A = 120^\circ\\

                   A = 60^\circ

from \ (1) \\A + B = 90^\circ\\60^\circ + B = 90^\circ\\B = 90^\circ - 60^\circ\\B = 30^\circ

                 

7 0
3 years ago
Are the two triangles below similar'? JKL
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Polynomial of degree 3 with three distinct real zeros and a positive leading coefficient
horsena [70]
Conjugate. i hoped that helped
7 0
3 years ago
Can someone help and explain ? thank you !
AfilCa [17]
\sf Hello!

\sf y = 2x^{2} + 4x - 3

\sf Discriminant :

= \sf b^{2} - 4ac

= \sf (4)^{2} - 4.(2).(-3)

= \sf 16 - (-24)

= \sf 16 + 24 = \sf 40

\sf Since,
\sf D \:is\:Greater\: than\: 0.

\sf Roots\: are\: Real\: and\: Distinct

\sf Hence,

\sf y = 2x^{2} + 4x - 3\: have\: A.\: Two\: real\: roots

~ \sf iCarl
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4 years ago
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