Polynomial of degree 3 with three distinct real zeros and a positive leading coefficient
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Answer:
Step-by-step explanation:
We are given the function:
and asked to find f(5). Therefore, we must substitute 5 in for each .
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
Multiply 18 and 5.
Add 90 and 11.
f(5) is equal to 101.