Programmers refer to programs that contain meaningful names as ____. AnswerThe answer is: Programmers refer to programs that con
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Answer:
The entire program is:
#include <iostream>
using namespace std;
int main() {
int userInt;
double userDouble;
char userChar;
string userString;
cout<<"Enter integer:"<<endl;
cin>>userInt;
cout<<"Enter double:"<<endl;
cin>>userDouble;
cout<<"Enter character:"<<endl;
cin>>userChar;
cout<<"Enter string:"<<endl;
cin>>userString;
cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl;
cout<<endl;
cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl;
cout<<endl;
cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl<<userDouble<<" cast to an integer is "<<(int)userDouble;
return 0; }
The program in C language:
#include <stdio.h>
int main() {
int userInt;
double userDouble;
char userChar;
char userString[50];
printf("Enter integer: \n");
scanf("%d", &userInt);
printf("Enter double: \n");
scanf("%lf", &userDouble);
printf("Enter character: \n");
scanf(" %c", &userChar);
printf("Enter string: \n");
scanf("%s", userString);
printf("%d %lf %c %s\n", userInt, userDouble, userChar, userString);
printf("\n");
printf("%d %lf %c %s\n%s %c %lf %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt);
printf("\n");
printf("%d %lf %c %s\n%s %c %lf %d\n%lf cast to an integer is %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt, userDouble, (int)userDouble); }
Explanation:
Lets do the program step by step:
1) Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output those four values on a single line separated by a space:
Solution:
The program is:
#include <iostream> //to use input output functions
using namespace std; //to identify objects cin cout
int main() { //start of main method
//declare an integer, a double, a character and a string variable
int userInt; //int type variable to store integer
double userDouble; //double type variable to store double precision floating point number
char userChar; //char type variable to store character
string userString; //string type variable to store a string
cout<<"Enter integer:"<<endl; //prompts user to enter an integer
cin>>userInt; //reads the input integer and store it to userInt variable
cout<<"Enter double:"<<endl; //prompts user to enter a double type value
cin>>userDouble; //reads the input double value and store it to userDouble variable
cout<<"Enter character:"<<endl; //prompts user to enter a character
cin>>userChar; //reads the input character and store it to userChar variable
cout<<"Enter string:"<<endl; //prompts user to enter a string
cin>>userString; //reads the input string and store it to userString variable
cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl; //output the values on a single line separated by space
So the output of the entire program is:
Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy
(2) Extend to also output in reverse.
Now the above code remains the same but add this output (cout) statement at the end:
cout<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt;
Now the output with the same values given as input is:
Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy
99 3.77 z Howdy Howdy z 3.77 99
(3) Extend to cast the double to an integer, and output that integer.
The rest of the code remains the same but add the following output (cout) statement in the end:
cout<<userDouble<<" cast to an integer is "<<(int)userDouble;
Now the output with the same values given as input is:
Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy Howdy z 3.77 99 3.77 cast to an integer is 3
Answer:
The combined output will be option D which is
This porridge is too hot.
This porridge is just right!
Explanation:
As the complete question is not the given the complete question is found online and is attached herewith.
Now from the given attached code
As the temperature value is 180 which is more than 90 so the first loop is true and the first print out is
This porridge is too hot.
Now the temperature is cooled down using the formula such that the temperature reduced 100 degrees in the intervals of 20 now the temperature becomes 80. As it is greater than 70, thus the second if loop is not executed.
As the temperature is 80 this the next print out will be as
This porridge is just right!
So the combined output will be option D which is
This porridge is too hot.
This porridge is just right!
Answer:
Go to explaination for the program code.
Explanation:
Before running the program you need to have these files created like below in your unix box.
Unix Terminal> cat nouns.txt
BOY
GIRL
BAT
BALL
Unix Terminal> cat articles.txt
A
THE
Unix Terminal> cat verbs.txt
HIT
SAW
LIKED
Unix Terminal> cat prepositions.txt
WITH
BY
Unix Terminal>
Code:
#!/usr/local/bin/python3
import random
def getWords(filename):
fp = open(filename)
temp_list = list()
for each_line in fp:
each_line = each_line.strip()
temp_list.append(each_line)
words = tuple(temp_list)
fp.close()
return words
articles = getWords('articles.txt')
nouns = getWords('nouns.txt')
verbs = getWords('verbs.txt')
prepositions = getWords('prepositions.txt')
def sentence():
return nounPhrase() + " " + verbPhrase()
def nounPhrase():
return random.choice(articles) + " " + random.choice(nouns)
def verbPhrase():
return random.choice(verbs) + " " + nounPhrase() + " " + prepositionalPhrase()
def prepositionalPhrase():
return random.choice(prepositions) + " " + nounPhrase()
def main():
number = int(input('Enter number of sentences: '))
for count in range(number):
print(sentence())
if __name__=='__main__':
main()
kindly check attachment for code output and onscreen code.
