Answer:
We need context, it could be several answers
Explanation:
Answer:
public String bananaSplit(int insertIdx, String insertText) {
return word.substring(0, insertIdx) + insertText + word.substring(insertIdx);
}
Explanation:
Do you have the other parts of the WordGames class?
Answer:
Thats good
Explanation:
Thanks for the points~! ;)
# Written in python
a = int(input("Enter an integer: "))
b = int(input("Enter an integer: "))
sum = a + b
# subtract the smaller number from the bigger
if a < b:
dif = a - b
else:
dif = b - a
prod = a * b
print("The sum is", sum)
print("The dif is", dif)
print("The product is", prod)
Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.