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lozanna [386]
2 years ago
6

Lines A and B are parallel. Line A is 3 units below line B. Line A is translated 9 units up to form line A′. Enter the distance,

in units, between lines A′ and B.
Mathematics
1 answer:
sweet [91]2 years ago
7 0

Answer:

it would be 27 units between line A and B

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Wich number does not represent a whole number
erica [24]
C. 20/4 because a fraction isn’t a whole number.
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3 years ago
Using Euler's relation, derive the following relationships:a. Cosθ=½(e^jθ+e^−jθ)b. Sinθ=½(e^jθ−e(^−jθ)
Montano1993 [528]

Answer:

a. cosθ = ¹/₂[e^jθ + e^(-jθ)] b. sinθ = ¹/₂[e^jθ - e^(-jθ)]

Step-by-step explanation:

a.We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Adding both equations, we have

e^jθ = cosθ + jsinθ

+

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ + cosθ + jsinθ - jsinθ

Simplifying, we have

e^jθ + e^(-jθ) = 2cosθ

dividing through by 2 we have

cosθ = ¹/₂[e^jθ + e^(-jθ)]

b. We know that

e^jθ = cosθ + jsinθ and

e^(-jθ) = cosθ - jsinθ

Subtracting both equations, we have

e^jθ = cosθ + jsinθ

-

e^(-jθ) = cosθ - jsinθ

e^jθ + e^(-jθ) = cosθ - cosθ + jsinθ - (-jsinθ)

Simplifying, we have

e^jθ - e^(-jθ) = 2jsinθ

dividing through by 2 we have

sinθ = ¹/₂[e^jθ - e^(-jθ)]

4 0
3 years ago
Simplify the expression p(p^-7*q^3)^-2*q^-3<br> A.p/q^3<br> B.p^15/q^9<br> C.1/(p^9*q^2<br> D.p^14*q
Alenkinab [10]

Answer:

B.p^15/q^9

Step-by-step explanation:

p(p^-7•q^3)^-2•q^-3

answer: B. p^15/q^9

3 0
3 years ago
What is the value of x in the figure Pls help​
Murljashka [212]

Answer: x=18

im assuming that this is a right angle

so if it is then that means the total of the angle should be 90 degrees. so 2x+3x should be equal to 90. Just combine like terms to get that 5x=90 and then isolate the variable (divide by 5 on both sides) so x ends up equaling 18.

so x=18

7 0
3 years ago
Find approximate radius of a circle that has an area of 60 square centimeters
elena-14-01-66 [18.8K]
Area of circle = πr^2
60=πr^2

we need to find radius (r)
so we solve for r
r^2=60/π
r=√(60/π)
r= 4.37
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